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3 years ago

What elements are bridges exposed to yearly?

Physics

1 answer:

xxMikexx [17]3 years ago

8 0

Possibly all of them, and then a few more. Tough things bridges ....

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If the white car experiences a change in momentum equal to 105,000 kg*m/s and is in contact with the red car for 5 seconds befor

larisa86 [58]

Answer:

21000 N

Explanation:

From the question given above, the following data were obtained:

Change in momentum = 105000 kg.m/s

Time = 5s

Force =?

Force is related to momentum and time according to the following formula:

Force = Change in momentum / time

With the above formula, we can calculate the force the white car experience during the collision. This can be obtained as illustrated below:

Change in momentum = 105000 kg.m/s

Time = 5s

Force =?

Force = Change in momentum / time

Force = 105000 / 5

Force = 21000 N

Thus, the white car experience a force of 21000 N during the collision.

4 0

3 years ago

A 17-mm-wide diffraction grating has rulings of 530 lines per millimeter. White light is incident normally on the grating. What

Sedbober [7]

Answer:

377 nm

Explanation:

Number of lines per meter is, $N &=530 \times 1000 \\ &=530000 \text { lines } / \mathrm{m} \end{aligned}$

Grating element is, $d=\frac{1}{N}$

$=1.8868 \times 10^{-6} \mathrm{~m}[tex]
Order is, n=5
Condition for maximum intensity is, [tex]d \sin \theta=n \lambda$

$\lambda &=\frac{1.8868 \times 10^{-6}}{5(\sin 90)} \\
&=0.377 \times 10^{-6} \mathrm{~m} \\
&=377 \mathrm{~nm}$

7 0

3 years ago

It took 50 joules to push a crate 2.5 meters. With what force was the crate pushed?

Inga [223]

It took 50 joules to push a crate 2.5 meters. With what force was the crate pushed?

7 0

2 years ago

¿ Cuáles son los principales aportes de las ciencias en el desarrollo del mundo? Menciona una aplicación de Física del contenido

maria [59]

Answer:earth, water, air, fire, and (later) aether, which were proposed to explain the nature and complexity of all matter in terms of simpler substances.

Explanation:

3 0

3 years ago

When the valve between the 2.00-L bulb, in which the gas pressure is 2.00 atm, and the 3.00-L bulb, in which the gas pressure is

padilas [110]

Answer:

$P_{C} = 3.2\, atm$

Explanation:

Let assume that gases inside bulbs behave as an ideal gas and have the same temperature. Then, conditions of gases before and after valve opened are now modelled:

Bulb A (2 L, 2 atm) - Before opening:

$P_{A} \cdot V_{A} = n_{A} \cdot R_{u} \cdot T$