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Wewaii [24]
3 years ago
10

A rocket is moving at 1/4 the speed of light relative to Earth. At the center of this rocket a light suddenly flashes. To an obs

erver at rest in the rocket a. the light will reach the front of the rocket before it reaches the back of the rocket. b. the light will reach the front of the rocket at the same instant that it reaches the back of the rocket. c. the light will reach the front of the rocket after it reaches the back of the rocket.
Physics
2 answers:
larisa [96]3 years ago
7 0

Answer:

The correct answer is;

b. the light will reach the front of the rocket at the same instant that it reaches the back of the rocket.

Explanation:

The speed of light is an invariant. The speed of light is independent of the source or the observer, that is the speed of light does not depend on the speed of the source, or the speed of the observer, or the speed of the medium. The speed of light is constant, and as such the light will arrive at the back and front of the rocket at the same time.

Sedaia [141]3 years ago
5 0

Answer:

B. the light will reach the front of the rocket at the same instant that it reaches the back of the rocket.

Explanation:

To an observer at rest in the rocket who can't see either sides of the rocket, the speed of the light is constant which means the distance to the front or the back is same and would appear to reach the rocket at the same time.

Although from the point of view of the person on the earth, the front of the rocket is travelling in opposite direction of the light while the back of the rocket is moving closer to the light. This means that the distance travelled by the light going forward will be longer going backwards. And since the speed of light is constant in both directions, the light will reach the back of the rocket before it reaches the front  for the observer on the earth.

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Suppose you are drinking root beer from a conical paper cup. The cup has a diameter of 10 centimeters and a depth of 13 centimet
sveta [45]

Answer:

The level of the root beer is dropping at a rate of 0.08603 cm/s.

Explanation:

The volume of the cone is :

V=\frac {1}{3}\times \pi\times r^2\times h

Where, V is the volume of the cone

r is the radius of the cone

h is the height of the cone

The ratio of the radius and the height remains constant in overall the cone.

Thus, given that, r = d / 2 = 10 / 2 cm = 5 cm

h = 13 cm

r / h = 5 / 13

r = {5 / 13} h

V=\frac {1}{3}\times \frac {22}{7}\times ({{{\frac {5}{13}\times h}}})^2\times h

V=\frac {550}{3549}\times h^3

Also differentiating the expression of volume w.r.t. time as:

\frac {dV}{dt}=\frac {550}{3549}\times 3\times h^2\times \frac {dh}{dt}

Given: \frac {dV}{dt} = -4 cm³/sec (negative sign to show leaving)

h = 10 cm

So,

-4=\frac{550}{3549}\times 3\times {10}^2\times \frac {dh}{dt}

\frac{55000}{1183}\times \frac {dh}{dt}=-4

\frac {dh}{dt}=-0.08603\ cm/s

<u>The level of the root beer is dropping at a rate of 0.08603 cm/s.</u>

3 0
3 years ago
Summarize the Venn diagram.
Elena L [17]

Answer:

If this is a multiple choice question, then the answer is D.

Explanation:

Compounds are composed of atoms, which are composed of subatomic particles and consist of matter. Since they are composed of atoms rather than vice-versa, compounds cannot be found inside atoms and are not the most basic form of matter (ruling out A and C). A pure substance contains atoms, which are each composed of subatomic particles. Therefore, a pure substance must have atoms if it contains subatomic particles (ruling out B). The only answer left is D.

5 0
3 years ago
I don’t know this one I need help
nikdorinn [45]
D
Using the kinetic energy 1/2mv^2 formula
5*10^5 is the answer
4 0
2 years ago
Through what vertical height is a 50 N object moved if 250 J of work is done lifting it against the gravitational field of Earth
zimovet [89]

5m

Explanation:

Given parameters:

Weight of object = 50N

Work done in lifting object = 250J

Unknown:

Vertical height = ?

Solution:

The work done on an object is the force applied to lift a body in a specific direction.

   Work done = force x distance

  Weight is a force in the presence of gravity;

  Work done = weight x height of lifting

Height of lifting = \frac{work done }{weight}

 Height of lifting = \frac{250}{50} = 5m

The vertical height through which the object was lifted is 5m

learn more:

Work done brainly.com/question/9100769

#learnwithBrainly

6 0
3 years ago
you throw an object straight up at 15m/s. how fast is it going when it gets back to the height from which you threw it?
laiz [17]
At the same speed because it will slow down as it approaches the peak then speed up as it goes down again


it will be going 15m/s when it gets to the same height if we neglect air resistance and the object doesn't hit something
8 0
3 years ago
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