Answer:
52.5°C
Explanation:
The final enthalpy is determined from energy balance where initial enthalpy and specific volume are obtained from A-12 for the given pressure and state
mh1 + W = mh2
h2 = h1 + W/m
h1 + Wα1/V1
242.9 kJ/kg + 2.35.0.11049kJ/ 0.35/60kg
=287.4 kJ/kg
From the final enthalpy and pressure the final temperature is obtained A-13 using interpolation
i.e T2 = T1 + T2 -T1/h2 -h1(h2 - h1)
= 50°C + 60 - 50/295.15 - 284.79
(287.4 - 284.79)°C
= 52.5°C
Because the act of braking is an example of negative acceleration.
Example: if the rate of braking was say 2 meters per second^2, and the starting velocity was 10 m/s, it would take 5 seconds to come to a stop(during those 5 seconds you would still be moving).
The magnitude of the displacement of the car from the starting point to halfway around the track is 256 m.
Answer:
Explanation:
Since the race track is a circular track, the distance for one lap will be equal to the circumference of the circular track. And the circumference will be equal to the circumference of the circle.
Since the radius of the track is given as 200 m, then the circumference of the circular track will be
Circumference = 2πr = 2 × 3.14 × 200
So the circumference of the circular track = 1256 m.
So the starting point or position of the track is considered as zero and if the car has traveled half way means, the car has covered half of the circumference of the track.
As the circumference = 1256 m, then half of the circumference of the circle = 1256/2 = 256 m.
So the displacement is the measure of difference between the final position and initial position. As here the initial position is zero and the final position is the halfway around the track which is equal to 256 m.
Then Displacement = Final-Initial = 256-0= 256 m.
So the magnitude of the displacement of the car from the starting point to halfway around the track is 256 m.
Answer:
final velocity =97km/h(change to m/s) =26.9m/s NEVER FORGET TO DO THAT BECAUSE TIME IS GIVEN IN SECONDS
initial velocity 0 m/s
time 8.4s
