Answer:
a) k = 2231.40 N/m
b) v = 0.491 m/s
Explanation:
Let k be the spring force constant , x be the compression displacement of the spring and v be the speed of the box.
when the box encounters the spring, all the energy of the box is kinetic energy:
the energy relationship between the box and the spring is given by:
1/2(m)×(v^2) = 1/2(k)×(x^2)
(m)×(v^2) = (k)×(x^2)
a) (m)×(v^2) = (k)×(x^2)
k = [(m)×(v^2)]/(x^2)
k = [(3)×((1.8)^2)]/((6.6×10^-2)^2)
k = 2231.40 N/m
Therefore, the force spring constant is 2231.40 N/m
b) (m)×(v^2) = (k)×(x^2)
v^2 = [(k)(x^2)]/m
v = \sqrt{ [(k)(x^2)]/m}
v = \sqrt{ [(2231.40)((1.8×10^-2)^2)]/(3)}
= 0.491 m/s
Frequency and wavelength are inversely proportional.
A shorter wavelength implies a higher frequency.
Answer:
dz = 7.136 (answer)
Explanation:
given height for kate's kite = 50 ft (say y)
due to drift it move towards east = dx = 7 ft
string maximum length = 107 ft ( say z)
we have to find change in z
that is dz
it will form a right angle triangle for x , y and z where x is base y is height and z is hypotenuse
so we get according to Pythagoras Theorem
...............(i)
by derivative both side consider y as constant
from (i) equation
now put the value and find dz
after solving these we get
dz = 7.136 (answer)
Answer:
<h3>a stationary electric charge, typically produced by friction, which causes sparks or crackling or the attraction of dust or hair.Static electricity has several uses, also called applications, in the real world. One main use is in printers and photocopiers where static electric charges attract the ink, or toner, to the paper. Other uses include paint sprayers, air filters, and dust removal. Static electricity can also cause damage.Static electricity is an imbalance of electric charges within or on the surface of a material. The charge remains until it is able to move away by means of an electric current or electrical discharge.</h3>
Answer:
The two small charged spheres are now 4.382 cm apart
Explanation:
Given;
distance between the two small charged sphere, r = 7.59 cm
The force on each of the charged sphere can be calculated by applying Coulomb's law;
where;
F is the force on each sphere
q₁ and q₂ are the charges of the spheres
r is the distance between the spheres
Therefore, the two small charged spheres are now 4.382 cm apart.
