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3 years ago

A bat hits a 0.150 kg baseball for

Physics

1 answer:

lara31 [8.8K]3 years ago

3 0

Answer:

11.85 kg m/s

Explanation:

impulse = mass ( change in velocity )

= mass ( final velocity - initial velocity )

= 0.150 ( 32.0 - (-47.0))

= 0.150 ( 32.0 +47.0)

= 0.150 (79)

= 11.85 kg m/s

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Zoe is shown two mystery boxes that are both 8,000cm3. Her teacher tells her that one mystery box is filled with rocks and the o

krek1111 [17]

Answer:

The box of rocks will have depression which can be seen without touching the box.

Explanation:

The density of rocks is very large as compared with napkins. So, the weight of the rocks will be much more greater than that of napkins.

As both boxes have same volume the heavier box will show depression on the lower surface as compared to the lighter box. So, the box of rocks will have depression which can be seen without touching the box.

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2 years ago

He more gentle the

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2 years ago

If the escalator pulls you up a slope of 30.0o and moves with a velocity of 3.10m/s. What is the vertical component of your v

ioda

Answer:

$1.55\ \text{m/s}$

$2.68\ \text{m/s}$

Explanation:

v = Velocity of the elevator = 3.1 m/s

$\theta$ = Angle of the slope = $30^{\circ}$

Vertical component is given by

$v_y=v\sin\theta\\\Rightarrow v_y=3.1\sin30^{\circ}\\\Rightarrow v_y=1.55\ \text{m/s}$

The vertical component of the velocity is $1.55\ \text{m/s}$ .

Horizontal component is given by

$v_x=v\cos\theta\\\Rightarrow v_x=3.1\times \cos30^{\circ}\\\Rightarrow v_x=2.68\ \text{m/s}$

The horizontal component of the velocity is $2.68\ \text{m/s}$ .

8 0

2 years ago

Assume this 1.20-mm-radius copper wire is electrically neutral in the Earth reference frame, in which it is at rest and carrying

agasfer [191]

Answer:

The charge density in the system is $4.25*10^4C/m$

Explanation:

To solve this problem it is necessary to keep in mind the concepts related to current and voltage through the density of electrons in a given area, considering their respective charge.

Our data given correspond to:

$r=1*10^{-3}m\\v = 5.2*10^{-4}m/s\\e= 1.6*10^{-19}C$

We need to asume here the number of free electrons in a copper conductor, at which is generally of $8.5 *10^{28}m^{-3}$

The equation to find the current is

$I = VenA$

Where

I =Current

V=Velocity

A = Cross-Section Area

e= Charge for a electron

n= Number of free electrons

Then replacing,

$I = (5.2*10^{-4})(1.6*10^{-19})(88.5 *10^{28})(\pi(1*10^{-3})^2)$

$I= 22.11a$

Now to find the linear charge density, we know that

$I = \frac{Q}{t} \rightarrow Q = It$

Where:

I: current intensity

Q: total electric charges

t: time in which electrical charges circulate through the conductor

And also that the velocity is given in proportion with length and time,

$V_d = \frac{l}{t} \rightarrow l = V_d t$

The charge density is defined as

$\lambda = \frac{Q}{l}\\\lambda = \frac{It}{V_d t}\\\lambda = \frac{I}{V_d}$

Replacing our values

$\lambda = \frac{22.11}{5.20*10{-4}}$

$\lambda= 4.25*10^4C/m$

Therefore the charge density in the system is $4.25*10^4C/m$

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3 years ago

A 75 kg man and a 100. Kg woman are playing tug of war on a frictionless surface. The man accelerates toward the woman at 2.0 m/

Artemon [7]

Complete Question

A 75 kg man and a 100. Kg woman are playing tug of war on a frictionless surface. The man accelerates toward the woman at 2.0 m/s2.How much force does she use to pull on the rope

Answer:

The value is $F = 150 \ N$