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lesantik [10]
3 years ago
11

A bat hits a 0.150 kg baseball for

Physics
1 answer:
lara31 [8.8K]3 years ago
3 0

Answer:

11.85 kg m/s

Explanation:

impulse = mass ( change in velocity )

              = mass ( final velocity - initial velocity )

               = 0.150 ( 32.0 - (-47.0))

                = 0.150 ( 32.0 +47.0)

                = 0.150 (79)

                = 11.85 kg m/s

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What would happen if the gravitational force between the moon suddenly disappeared?
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So many thinks the water wouldnt have as many waves it could result in no season and even an ice age. Nights would be darker. In result in the tides changing animals will be confused, some species rely on the tides for food and shelter. So without that it would cause a chain of mass extinction.
8 0
3 years ago
A cyclist rides at a constant speed of 4. 5 m/s around a curve. If the centripetal acceleration is 29 m/s2, what is the radius o
QveST [7]

Answer:

a = v^2 / R = 4.5^2 / R = 29

R = 4.5^2 / 29 = .70 m

     

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2 years ago
A car is traveling at 96km/hr. what is the acceleration of a car traveling a distance of 100m and come to rest?​
8090 [49]

Answer:

Explanation:

v² = u² + 2as

v = 0

u = 96 / 3.6 = 26.7 m/s

0² = 26.7² + 2a100

a = -3.5555555... ≈ -3.6 m/s²

the negative sign indicated the acceleration vector opposes the (assumed positive) initial velocity vector direction.

6 0
2 years ago
If a girl is running along a straight road with a uniform velocity 1.5m/s find her acceleration ​
Jlenok [28]

Answer:

Dear user,

Answer to your query is provided below

Acceleration is zero because of no change in velocity.

Explanation:

Remember that velocity is a vector quantity and a vector can change in 3 ways

•Magnitude only

•Direction only

•Both magnitude and direction.

Now the magnitude of velocity (speed) can stay constant while the direction is changing. This is the case in circular motion.

In the question above, it is mentioned that the girl is moving along a straight road. Therefore no change in direction of velocity.

7 0
3 years ago
What is the magnitude of the velocity when the elastic potential energy is equal to the kinetic energy? (Assume that U=0 at equi
zhannawk [14.2K]

Answer:

Explanation:

General Equation of SHM is given by

x=A\cos \omega t

v=-A\omega \sin \omega t

where x=position of particle

A=maximum Amplitude

\omega =angular frequency

t=time

At any time Total Energy is the sum of kinetic Energy and Elastic potential Energy i.e. \frac{1}{2}kA^2

where k=spring constant

Potential Energy is given by U=\frac{1}{2}kx^2

also it is given that Potential Energy(U) is equal to Kinetic Energy(K)

Total Energy=K+U

Total=2U=2\times \frac{1}{2}kx^2

\frac{1}{2}kA^2=2\times \frac{1}{2}kx^2

x=\pm \frac{A}{\sqrt{2}}

at x=\frac{A}{\sqrt{2}}

velocity is v=\frac{A\omega}{\sqrt{2}}

6 0
3 years ago
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