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OLga [1]
3 years ago
12

Which of the following is an example of how pictures of a planet's surface can provide evidence about the planet's natural resou

rces?
A.
Pictures showing craters suggest the presence of gold.
B.
Pictures showing clouds suggest the presence of free oxygen.
C.
Pictures showing rocks suggest the presence of natural gas.
D.
Pictures showing valleys suggest the presence of water.
Physics
1 answer:
Volgvan3 years ago
5 0
I think it’s c but I’m not for sure
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Which policy might help eliminate a disadvantage of renewable energy resources? A. modernizing coal power plants B. storing nucl
Viefleur [7K]
I believe the answer is D
3 0
4 years ago
Ann walks 80 meters on a straight line 33degrees north of east starting at point 1. Draw Ann's path. Represent Ann's walk with a
zubka84 [21]
The x-component of Anne's path:
80 x cos(33)
= 67.1 meters
y-component of Anne's path:
80 x sin(33)
= 43.6 meters
To draw he diagram, you draw a horizontal line starting at point 1 to the right representing 67.1 meters. At the end of this line, draw a vertical line upwards representing 43.6 meters.
Connect the start of the horizontal line at point 1 to the end of the vertical line with an angle of 33° between them.
7 0
3 years ago
The Sun’s surface temperature is about 5800 K and its spectrum peaks at 5000 Å. An O-type star’s surface temperature may be 40,0
vova2212 [387]

Answer:

Part a)

\lambda_2 = 725 A^o

Part b)

This range of wavelength exist in the region of X rays

So correct answer will be X Rays

Part c)

No it is not visible because this energy can not travel to large distance

Explanation:

Part a)

As per Wein's law we know that

\lambda_1T_1 = \lambda_2 T_2

so we know that

\lambda_1 = 5000A^o

T_1 = 5800 K

T_2 = 40,000 K

now we have

\lambda_2 = \frac{5000 \times 5800}{40,000}

\lambda_2 = 725 A^o

Part b)

This range of wavelength exist in the region of X rays

So correct answer will be X Rays

Part c)

No it is not visible because this energy can not travel to large distance

7 0
3 years ago
The driver of a pickup truck accelerates from rest to a speed of 37 mi/hr over a horizontal distance of 215 ft with constant acc
Alona [7]

Answer:

Maximum shearing force developed in each of the two pegs during acceleration is 1830 lbf

Explanation:

First we will find the acceleration of pickup truck.

As, the acceleration is uniform, therefore we can use Newton's third equation of motion:

2as = V_{f}^{2}-V_{i}^{2}

First convert speed into ft/sec

1 mile/hr = 1.47 ft/sec

therefore,

37 mile/hr = 37 x 1.47 ft/sec

37 mile/hr =  54.39 ft/sec

with initial speed 0 ft/sec (starting from rest), using in equation of motion:

a = [(54.39 ft/sec)² - (0 ft/sec)²]/2(215 ft)

a = 6.88 ft/sec²

Now, the total shear force will be given by Newton's second law of motion:

F = ma

F = (460 lbm +72 lbm)(6.88 ft/sec²)

F = 3660 lbf

Now for the max shear force in each of the two pegs we divide total fore by 2:

Force in each peg = F/2 = (3660 lbf)/2

<u>Force in each peg = 1830 lbf</u>

4 0
3 years ago
Which two of the following are the densest of the materials shown?
Harrizon [31]
The correct answer is: rock 1000 and bottle of soda 2000
7 0
3 years ago
Read 2 more answers
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