First we need to find the voltage difference between the initial and final location of the electron.
Since the electron travelled for a distance d=5 m in an uniform electric field of intensity E=300 N/C, the voltage difference between the final and initial location is
And then, we can calculate the change in potential energy of the electron, which is the product between the charge of the electron and the voltage difference:
And the negative sign is due to the fact that we assumed the electron traveled in the natural direction of the electric field, so traveling from a point at lower voltage to a point at higher voltage (the sign of
is positive), so since it's a negative charge the electron is losing potential energy.
Answer:
-47 J
Explanation:
Given that,
Heat loss = -76 J (negative for loss)
Work done by the surroundings = -29 J
We need to find the change in internal energy of a system.
The first law of thermodynamics is given by :
W is work done by the system
Putting all the values,
Hence, the change in internal energy is -47 J.
Answer:
a) the angular velocity is ω= 82 rad/seg
b) the tangencial acceleration is a = 1.148 m/s²
c) the centripetal acceleration is ac = 941.36 m/s²
Explanation:
for rotational motion
ω= angular velocity
ωo = initial angular velocity
α= angular acceleration
t = time
R= radius
a= tangencial acceleration
ac = centripetal acceleration
a) ω= ωo + α*t = 0 + 8.2 rad/s2 * 10 s = 82 rad/seg
b) a= α*R = 8.2 rad/s2* 14 cm = 114.8 cm/s² = 1.148 m/s²
c) ac= ω²*R = (82 rad/seg)² * 14 cm = 94136 cm/s² = 941.36 m/s²
An object moving with constant acceleration near the surface of the earth is influenced by the gravity. <span>In physics, </span>gravitational acceleration<span> is the </span>acceleration<span> on an object caused by the force of </span>gravitation<span>. Neglecting friction such as air resistance, all small bodies accelerate in a </span>gravitational <span>field at the same rate relative to the center of mass.</span>
Answer:
onservation of energy
U top = K bottom
(m + m)*g*L = 1/2*I*?^2 where I = m*(L/2)^2 + m*L^2 = 1.25*m*L^2
So 2m*g*L = 1/2*1.25*m*L^2*?^2
So ? = sqrt(3*g*/(1.25*L) ) = sqrt(12g/5L)