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dusya [7]
3 years ago
15

1 point

Physics
1 answer:
Oduvanchick [21]3 years ago
5 0
The distance it traveled is 147
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A block of concrete has a mass of 48kg a crane lifts the block to a height of 12m above the ground calculate the gravitational p
Afina-wow [57]

Answer:

5760 J

Explanation:

From the question given above, the following data were obtained:

Mass of block = 48 kg

Height (h) = 12 m

Gravitational field strength (g) = 10 N/Kg

Gravitational potential energy (PE) =?

The gravitational potential energy stored by the block can simply be obtained as follow:

PE = mgh

PE = 48 × 10 × 12

PE = 5760 J

Therefore, the gravitational potential energy stored by the block is 5760 J

3 0
3 years ago
Listed in the Item Bank are some important labels for sections of the image below. To find out more information about labels, so
erica [24]

1 - cytoplasm

2 - DNA

3 - rybosome

4 - cell membrane

5 - nucleus

5 0
3 years ago
Give me 3 events of matter and energy that you can't explain yourself ( need some ideas)​
nalin [4]

Answer:

Plasma, Supersolid, Superfluid

Explanation:

I don't know if this is what you are looking for, but I have no idea what these even are.

8 0
3 years ago
Which one of the following SI base units is not matched to the correct unit of measurement?
ahrayia [7]
C.Lenth: Km; This answer isn´t correct.

the correct unit of measurement of length is "m".

6 0
3 years ago
Read 2 more answers
A 16 pound weight attached to a spring exhibits simple harmonic motion. Determine the equation of motion if the spring constant
yarga [219]

Answer:

T = 2.82π s

x = Acos(0.71t)

Explanation:

This problem can be solved by using the expressions

T = 2\pi \sqrt{\frac{m}{k} }    ( 1 )

x=Acos(\omega t) = Acos(\frac{2\pi }{T}t )   ( 2 )

where T is the period of oscillation of the system, m is the mass of the object attached to the spring, k is the spring constant and x is the position of the object.

By replacing in the expression (1):

T=2\pi \sqrt{\frac{16 lb}{8lb/ft}} = 2.82\pi s

Taking 6 inches as the amplitude of the motion, we have

x=6cos(\frac{2\pi }{2.82\pi }t ) = 6cos(0.71t)

I hope this is useful for you

Regards

8 0
3 years ago
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