All categories

3 years ago

Why is it dangerous to not have the right grade motor oil for the climate you drive in?

Chemistry

2 answers:

IgorLugansk [536]3 years ago

6 0

Answer:

When temperature increases the viscosity of the oil decreases and flows too freely through the engine.

When temperature decreases the viscosity of the oil increases and does not flow fast enough through the engine.

Explanation:

When liquids flow they experience a drag in their forward movement. This drag force is called viscosity which acts in the opposite direction to the flow of the liquid.

As temperature increases the kinetic energy of the liquid particles also increases which then reduces the drag force or viscosity. Similarly as temperature decreases the kinetic energy of the liquid particles also decreases which then increases the drag force or viscosity.

Roman55 [17]3 years ago

5 0

Actually its the second and fourth one for sure! If you just put one it only gives parcel credit. ;-;

You might be interested in

How to know what gases have more effusion?

OlgaM077 [116]

Answer:

If you have ever been in a room when a piping hot pizza was delivered, you have been made aware of the fact that gaseous molecules can quickly spread throughout a room, as evidenced by the pleasant aroma that soon reaches your nose. Although gaseous molecules travel at tremendous speeds (hundreds of meters per second), they collide with other gaseous molecules and travel in many different directions before reaching the desired target.

Explanation:

hope this helps

6 0

2 years ago

HelapPPPpPPPPpThe three states of matter that may change during a physical change are O atoms, molecules, electrons O color, sha

crimeas [40]

Answer:

Solid liquid and gas

Explanation:

3 0

2 years ago

It might be to long but please help. I did search but couldn't find answer

Inessa05 [86]

The events that occur is based on the type of hormone being released. Like puberty. It's an event coming from different types of hormones being sent to a tissue

7 0

3 years ago

Which best represents the reaction of calcium and zinc carbonate (ZnCO3) to form calcium carbonate (CaCO3) and zinc?

Basile [38]

Answer:

the second one

Explanation:

Ca+ZnCO3 is the same as calcium + zinc -> is equal to CaCo3+Zn and that is calcium carbonate +zinc which is what the statement states

8 0

2 years ago

Read 2 more answers

When calcium carbonate is heated, it decomposes to produce calcium oxide and carbon dioxide, as shown in the diagram below. How

Vikki [24]

Explanation:

Before we start with any calculation, we need to determine the stoichiometric relationship between the reactants consumed and the products formed. In other words, we need to establish a balanced chemical equation that describes the decomposition of calcium carbonate as shown below.

$\text{CaCO}_{3} \ \ \text{(s)} \ \overset{\Delta}{\longrightarrow} \ \text{CaO} \ \text{(s)} \ + \ \text{CO}_{2} \ \text{(g)}$ ,

where the uppercase delta symbol, $\Delta$ , above the chemical reaction arrow denotes that heat is applied to make the reaction proceed in the direction of the arrow.

To calculate how many moles are there in 4 grams of calcium carbonate, we use the relation

$n \ = \ \displaystyle\frac{m}{M_{r}}$ ,

where $n$ is the number of moles, $m$ is the mass of the chemical substance and $M_{r}$ is the molar mass of the chemical substance. We first need to identify the molar mass of calcium carbonate,

$M_{r} \, [\text{CaCO}_{3}] \ = \ A_{r} \, [\text{Ca}] \ + \ A_{r} \, [\text{C}] \ + \ 3 \, \times \, A_{r} \, [\text{O}] \\ \\ M_{r} \, [\text{CaCO}_{3}] \ = \ 40.078 \ + \ 12.011 \ + \ 3 \, \times \, 15.999 \\ \\ M_{r} \, [\text{CaCO}_{3}] \ = \ 100.086 \ \text{g mol}^{-1}$

Hence,

$n \ = \ \displaystyle\frac{4 \ \text{g}}{100.086 \ \text{g mol}^{-1}} \\ \\ \\ n \ = \ 0.04 \ \text{mol}$ .

We know that, from the balanced chemical equation above, 1 mole of calcium carbonate following decomposition, will theoretically lead to the production of 1 mole of carbon dioxide. Then, if 0.04 moles of calcium carbonate is decomposed, then, 0.04 moles of carbon dioxide is produced.

To convert the number of moles into the mass of carbon dioxide produced, we need to rearrange the formula as follows.

$n \ = \ \displaystyle\frac{m}{M_{r}} \\ \\ \\m \ = \ n \ \times \ {M_{r}}$ .

Thus,

$M_{r} \, [\text{CO}_{2}] \ = \ A_{r} \, [\text{C}] \ + \ 2 \, \times \, A_{r} \, [\text{O}] \\ \\ M_{r} \, [\text{CO}_{2}] \ = \ (12.011 \ + \ 2 \, \times \, 15.999) \ \text{g mol}^{-1} \\ \\ M_{r} \, [\text{CO}_{2}] \ = \ 44.009 \ \text{g mol}^{-1}$

$\rule{12cm}{0.01cm}$

$m \ = \ 0.04 \ \text{mol} \ \times \ 44.009 \ \text{g mol}^{-1} \\ \\ m \ = \ 1.76 \ \text{g}$

Therefore, 4 grams of calcium carbonate yields 1.76 grams of carbon dioxide following decomposition.

6 0

2 years ago