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Rufina [12.5K]
3 years ago
6

If a metal donates or loses an electron it becomes a.. A. Ionic B. Covalent C. Metallic

Chemistry
2 answers:
gladu [14]3 years ago
5 0

Answer:

the answer to your question is c

pav-90 [236]3 years ago
3 0

Answer:

c

Explanation:

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What properties differentiate an ionically bonded compound from a covalently bonded compound
zaharov [31]

Answer:

ionically bonded compound transfer its electrons while covalently bonded compound share their electrons. ionically bonded compounds are charged while covalently bonded compound are neutral

6 0
3 years ago
Help asap ill give branilsit
stiks02 [169]
A prokaryotic cell is a cell without a nucleus (there's more to it, though).

Let's start from the bottom.

Strawberry plant: Plant cells are eukaryotic (cells have nucleus).
Hippopotamus: Animal cells are eukaryotic (cells have nucleus).
Paramecium: That's an animal, and animal cells are eukaryotic (cells have nucleus).
Bacterium: Perfect! Bacterium are prokaryotes! (cells don't have nucleus).

Your answer is bacterium.

Have an awesome day! :)
3 0
3 years ago
Would an element with 7 valence electrons be more or less reactive than an element with 3 valence electrons?
Sedbober [7]

Answer:

That would be more

Explanation:

5 0
4 years ago
In the equation N2(g) + 3H2(g)--- 2NH3(g), how many liters of hydrogen
Delicious77 [7]

Answer:

30 L H2

Explanation:

  • 10 L N2 x <u>3 L H2</u> = 30 L H2

.                         1 L N2

Try to verify my answer, Stoichiometry is not easy for me.

3 0
3 years ago
Read 2 more answers
Im hvaing a hard time getting the right answer
Tanya [424]

Answer:

V=23.9mL

Explanation:

Hello!

In this case for the solution you are given, we first use the mass to compute the moles of CuNO3:

n=2.49g*\frac{1mol}{125.55 g}=0.0198mol

Next, knowing that the molarity has units of moles over liters, we can solve for volume as follows:

M=\frac{n}{V}\\\\V=\frac{n}{M}

By plugging in the moles and molarity, we obtain:

V=\frac{0.0198mol}{0.830mol/L}=0.0239L

Which in mL is:

V=0.0239L*\frac{1000mL}{1L}\\\\V=23.9mL

Best regards!

6 0
3 years ago
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