(2m west) + (3m south) + (4m east) + (1m north) =
[ (2m west)+(4m east) ] + [ (3m south)+(1m north) ] =
[ (-2m east)+(4m east) ] + [ (3m south)-(1m south) ] =
(2m east) + (2m south)
Now, so far, we have the orthogonal (perpendicular) components of the displacement ... the North/South component and the East/West component.
To combine these, it's time for Pythagoras:
Displacement = √[ (2m)² + (2m)² ]
Displacement = √ (4m² + 4m²)
Diplacement = √8m²
<em>Displacement = 2.83 meters Southeast</em>
<u>Answer</u>
46,200 J
The energy of given out when a substance is losing heat is given by:
H = mcΔθ
Where m is the mass of the substance,
c is the specific heat capacity of the substance and
Δθ is the temperature change.
H = 0.50 × 22 4200
= 46,200 Joules.
Answer:
The pressure is 
Explanation:
From the question we are told that
The depth of the swimming pool is 
The density of water is 
Generally the total pressure exerted on the bottom of the swimming pool is mathematically represented as
Here 
is the atmospheric pressure with value
So
![P = 101325 + [1000 * 9.8 * 3]](https://tex.z-dn.net/?f=P%20%3D%20101325%20%2B%20%5B1000%20%2A%209.8%20%2A%203%5D)
=> 
=>
Edison's education is most unique and relevant.
1. The first teacher he had was his mother
2. He found vital lessons and was influenced greatly by the book of R.G. Parker called School of Natural Philosophy
3. Another educating piece he had was a book entitled The Cooper Union for the Advancement of Science and Art
His style of learning was though reading books on a variety of subjects, a self-educating environment that fosters independent learning which can be useful through his life.
