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Advocard [28]
3 years ago
6

1. A car begins at a speed of 3 m/s and accelerates at 2 m/s2

Physics
1 answer:
mina [271]3 years ago
8 0

Explanation:

v^2 = u^2 + 2as

v^2 = 9 + 160

v^2 = 169

v = 13

You might be interested in
The four wheels of a car are connected to the car's body by spring assemblies that let the wheels move up and down over bumps an
maksim [4K]

Answer:

The approximate  spring constant is  k =  55533.33 \  N/m

Explanation:

From the question we are told that

   The  mass of the person is  m =  68 \ kg

     The  dip of the car is  x =  1.2 \ cm  =  0.012 \ m

Generally according to hooks law  

        F  =  k * x

here the force F is the weight of the person which is mathematically represented as

         F =  m * g

=>    m * g  =  k * x

=>     k  =  \frac{m * g }{x }

=>    k  =  \frac{68 *  9.8}{ 0.012}

=>   k =  55533.33 \  N/m

8 0
3 years ago
11 kg is a familiar weight for a bag of flour. You are baking cookies for a Save The Rain Forest fund drive. It takes 500 g of f
arlik [135]

Answer: 22 batches.

Explanation:

Given that 11 kg is a familiar weight for a bag of flour. Also, it is given that It takes 500 g of flour to make one batch of cookies.

How many batches of cookies can you make with one bag of flour

Let's first convert 11 kg into grams (g) by multiplying it by 1000

11 × 1000 = 11000 g

Divide 11000 by 500

11000/500 = 22

Therefore, 22 batches of cookies can be made with one bag of flour.

8 0
3 years ago
You are driving to the grocery store at 14 m/s. You are 115 m from an intersection when the traffic light turns red. Assume that
kogti [31]

Answer:

111.5 m

Explanation:

Given that You are driving to the grocery store at 14 m/s. You are 115 m from an intersection when the traffic light turns red. Assume that your reaction time is 0.50 s and that your car brakes with constant acceleration. 

Use first equation of motion

V = U - at

Since the car is going to rest, V = 0 and a = negative

0 = 14 - a × 0.5

0.5a = 14

a = 14 /0.5

a = 28 m/s^2

Let us use second equation of motion

S = Ut - 1/2at^2

S = 14 × 0.5 - 0.5 × 28 × 0.5^2

S = 7 - 3.5

S = 3.5 m

115 - 3.5 = 111.5

Therefore, you are 111.5 metres from the intersection (in m) when you begin to apply the brakes.

6 0
3 years ago
An object is allowed to fall freely near the surface of a planet. The object has an acceleration due to gravity of 24 m/s2. How
Alborosie

Answer:

12 m

Explanation:

The object is in uniformly accelerated motion, so the distance covered can be found using the following suvat equation:

s=ut+\frac{1}{2}at^2

where

s is the distance

u is the initial velocity

t is the time

a is the acceleration

For this problem,

g=24 m/s^2

and

u = 0, since we are considering the first second of motion

So, substituting t = 1 s, we find

s=0+\frac{1}{2}(24)(1)^2=12 m

6 0
3 years ago
A skier descends a mountain at an angle of 35.0º to the horizontal. If the mountain is 235 m long, what are the horizontal and v
neonofarm [45]
Total displacement along the length of mountain is given as
L = 235 m
angle of mountain with horizontal = 35 degree
now we will have horizontal displacement as
x = L cos35
x = 235 cos35 = 192.5 m
similarly for vertical displacement we can say
y = L sin35
y = 235 sin35 = 134.8 m
6 0
3 years ago
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