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Kobotan [32]
1 year ago
10

Suppose the wavelength of the light is 460 nm. how much farther is it from the dot on the screen in the center of fringe e to th

e left slit than it is from the dot to the right slit?
Physics
1 answer:
gavmur [86]1 year ago
3 0

The difference is 920nm.

<h3>What is called Wavelength?</h3>

The wavelength can be defined as the separation between wave crests. Additionally, a wide variety of objects move in waves, including light, the earth or ground, water, strings, air, and sound waves. Furthermore, we use the Greek letter lambda to denote the wave's wavelength. In addition, the wave's wavelength is determined by dividing its velocity by its frequency. Additionally, we employ meters (m), which is the unit used to indicate wavelength in meters.

Positive interference is produced by a bright fringe, and the wavelength is always multiple.

The difference at the center fringe is (460 nm)(0) = 0.

The difference for the first maximum is (460 nm)(1) = 460 nm.

The difference for the second maximum is (460 nm)(2) = 920 nm.

As a result, the difference for maxima n is (460 nm) (n)

Since C is on the second maximum in the image that was submitted, the difference is stated as (460 nm)(2) = 920 nm.

Consequently, the screen's central dot on the fringe E to the left slit is 920 nm.

To learn more about Wavelength, visit:

brainly.com/question/13533093

#SPJ4

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