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saveliy_v [14]
3 years ago
12

A 10-meter-long spear is thrown at a relativistic speed through a 10-meter-long pipe (both measured when at rest.) when the spea

r passes through the pipe,
a. the pipe shrinks so the spear extends at both ends.
b. both shrink equally so the pipe barely covers the spear.
c. the spear shrinks so the pipe completely covers it.
d. any of the above, depending on the motion of the observer
e. none of the above
Physics
1 answer:
Mekhanik [1.2K]3 years ago
8 0
The correct answer is a
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Help me with thisssss<br>m= 5kg<br>l= 10m<br>l¹= 1m<br>l²= 2m<br>T¹, T² =??​
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18 1/2 po

Explanation:

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The force on a wire is a maximum of 4.50×10−2 N when placed between the pole faces of a magnet. The current flows horizontally t
Vladimir [108]

Answer:

a) Southpole

b) 1.875 A

c) 4.43 x 10-2 N

Explanation:

a) The magnetic force,

               FB = IdlxB

As the wire jumps towards the observer,  this means that the force on the wire is out of the plane of the paper or along the Z axis(horizontally) taking current along the X axis and B along the Y axis.

The vector cross product dLxB is along +ve Z axis only if the B field is vertically upward,along the Y axis. Therefore, the top pole face must be a South pole.

b) D= 15 cm = 0.15 m is the length of the wire in the magnetic field B

The max force, Fm = BIL

         I =Fm/B.L = 4.5x10^-2/0.16x0.15      

          = 1.875 A

The current in the wire is therefore 1.875 Amps

c) The wire is tipped at 10.0° with the horizontal means,

the angle between the wire(dL) and magnetic field B is 90° -10° = 80°

The, Force, F = BIL sin 80°

                     = Fm.sin 80° = 4.5x10^-2 x0.9848

                     = 4.43 x 10-2 N

The effective length of the wire in the field,

                L' = L cos 10°

Then,          F= BIL cos 10°

                     = Fm.cos 10° = 4.5x10^-2 x0.9848

                     = 4.43 x 10-2 N

4 0
3 years ago
An object of mass 50 kg moves with a speed of 10m/s. Calculate the kinetic energy of the object?
S_A_V [24]
Mass = 50kg
velocity = 10m/s
KE = 1/2 mv^2
= 1/2 × 50 × 10^2
= 2500J
7 0
3 years ago
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