What is the atomic mass of silicon

2 answers:

7 0

The atomic number of Silicon is 14. So there are 14 protons in the nucleus of every Silicon atom. But that's not the mass. Besides the protons, there are also some neutrons, and the atomic mass of the atom is the total number of (protons + neutrons) in its nucleus.

The number of neutrons is not the same in every Silicon atom. There are 3 stable isotopes of Silicon. A Silicon nucleus can have 14, 15 or 16 neutrons.

So an atom of Silicon can have an atomic mass of 28, 29, or 30.

emmainna [20.7K]2 years ago

5 0

<h2>The atomic mass of silicon is 28.0855</h2>

You might be interested in

An alpha particle (the nucleus of a helium atom) consists of two protons and two neutrons, and has a mass of 6.64 * 10-27 kg. A

melamori03 [73]

Answer:

t = 4.21x10⁻⁷ s

Explanation:

The time (t) can be found using the angular velocity (ω):

$\omega = \frac{\theta}{t}$

Where θ: is the angular displacement = π (since it moves halfway through a complete circle)

We have:

$t = \frac{\theta}{\omega} = \frac{\theta}{v/r}$

Where:

v: is the tangential speed

r: is the radius

The radius can be found equaling the magnetic force with the centripetal force:

$qvB = \frac{mv^{2}}{r} \rightarrow r = \frac{mv}{qB}$

Where:

m: is the mass of the alpha particle = 6.64x10⁻²⁷ kg

q: is the charge of the alpha particle = 2*p (proton) = 2*1.6x10⁻¹⁹C

B: is the magnetic field = 0.155 T

Hence, the time is:

$t = \frac{\theta*r}{v} = \frac{\theta}{v}*\frac{mv}{qB} = \frac{\theta m}{qB} = \frac{\pi * 6.64 \cdot 10^{-27} kg}{2*1.6 \cdot 10^{-19} C*0.155 T} = 4.21 \cdot 10^{-7} s$