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Sladkaya [172]
3 years ago
13

Covert 12.64 g NaOH to moles

Chemistry
2 answers:
grandymaker [24]3 years ago
7 0
No of moles = mass/molar mass
mass = 12.64 g
molar mass = 40 g/mol
no of moles = 12.64/40
no of moles = 0.316 g
mezya [45]3 years ago
3 0
To calculate moles, use the formula Mol = Mass/ Mr.... Mr of NaOH is 23+ 16 + 1 = 40.... Mol = 12.64/40 = 0.316
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Chemical change or process
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Answer:

I think the answer is c!

Explanation:

Pure substances are further broken down into elements and compounds. Mixtures are physically combined structures that can be separated into their original components. A chemical substance is composed of one type of atom or molecule. hope this helps you!

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What is technology?
ella [17]

Something created for using science for use by society. Hence, option A is correct.

<h3>What is science?</h3>

Science is the pursuit and application of knowledge and understanding of the natural and social world following a systematic methodology based on evidence.

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6 0
2 years ago
The CRC Handbook, a large reference book of chemical and physical data, lists two isotopes of indium (). The atomic mass of 4.28
ivanzaharov [21]

<u>Answer:</u> The mass of second isotope of indium is 114.904 amu

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

  .....(1)

Let the mass of isotope 2 of indium be 'x'

  • <u>For isotope 1:</u>

Mass of isotope 1 = 112.904 amu

Percentage abundance of isotope 1 = 4.28 %

Fractional abundance of isotope 1 = 0.0428

  • <u>For isotope 2:</u>

Mass of isotope 2 = x amu

Percentage abundance of isotope 2 = [100 - 4.28] = 95.72 %

Fractional abundance of isotope 2 = 0.9572

Average atomic mass of indium = 114.818 amu

Putting values in equation 1, we get:

114.818=[(112.904\times 0.0428)+(x\times 0.9572)]\\\\x=114.904amu

Hence, the mass of second isotope of indium is 114.904 amu

4 0
3 years ago
How many molecules of co2 in 97.3 grams of co2
s2008m [1.1K]

Answer:

1.33 × 10²⁴ molecules CO₂

General Formulas and Concepts:

<u>Chemistry - Stoichiometry</u>

  • Reading a Periodic Table
  • Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

97.3 g CO₂

<u>Step 2: Define conversions</u>

Avogadro's Number

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Molar Mass of O - 16.00 g/mol

Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol

<u>Step 3: Convert</u>

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<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules.</em>

1.33138 × 10²⁴ molecules CO₂ ≈ 1.33 × 10²⁴ molecules CO₂

8 0
3 years ago
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