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Sladkaya [172]
3 years ago
13

Covert 12.64 g NaOH to moles

Chemistry
2 answers:
grandymaker [24]3 years ago
7 0
No of moles = mass/molar mass
mass = 12.64 g
molar mass = 40 g/mol
no of moles = 12.64/40
no of moles = 0.316 g
mezya [45]3 years ago
3 0
To calculate moles, use the formula Mol = Mass/ Mr.... Mr of NaOH is 23+ 16 + 1 = 40.... Mol = 12.64/40 = 0.316
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What is the molarity of a 0.25-liter solution containing 52 grams of HBr? (1 point)
Pani-rosa [81]

2.6 M hBr

This would be the correct answer.

3 0
3 years ago
Calculate the pressure of the CO₂ (g) in the container at 425 K.
Elanso [62]

The pressure of the CO₂ = 0.995 atm

<h3>Further explanation</h3>

The complete question

<em>A student is doing experiments with CO2(g). Originally, a sample of gas is in a rigid container at 299K and 0.70 atm. The student increases the temperature of the CO2(g) in the container to 425K.</em>

<em>Calculate the pressure of the CO₂ (g) in the container at 425 K.</em>

<em />

<em />

Gay Lussac's Law

When the volume is not changed, the gas pressure is proportional to its absolute temperature

\tt \dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}

P₁=0.7 atm

T₁=299 K

T₂=425 K

\tt P_2=\dfrac{P_1\times T_2}{T_1}\\\\P_2=\dfrac{0.7\times 425}{299}=0.995 `atm

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6 0
3 years ago
if you mixed 72.9g hydrochloric acid(aq) with 150g silver acetate(aq), what would be the limiting reagent?​
horsena [70]

Answer:

                      Silver Acetate would be the Limiting Reagent.

Explanation:

                    The balance chemical equation for the given double displacement reaction is as;

                            HCl + AgC₂H₃O₂ → AgCl + HC₂H₃O₂

Step 1: <u>Calculate Moles of Starting Materials:</u>

Moles of HCl:

                      Moles  =  Mass / M.Mass

                      Moles  =  72.9 g / 36.46

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Moles of AgC₂H₃O₂:

                      Moles  =  150 g / 166.91 g/mol

                      Moles  =  0.898 moles

Step 2: <u>Find out Limiting reagent as:</u>

According to balance chemical equation.

              1 mole of HCl reacts with  =  1 mole of AgC₂H₃O₂

So,

         1.99 moles of HCl will react with  =  X moles of AgC₂H₃O₂

Solving for X,

                     X =  1.99 mol × 1 mol / 1 mol

                     X =  1.99 mol of AgC₂H₃O₂

Hence, to completely consume 1.99 moles of Hydrochloric acid we will require 1.99 moles of Silver Acetate, But, we are provided with only 0.898 moles of Silver Acetate. This means Silver Acetate will consume first in the reaction therefore, it is the LIMITING REAGENT.

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yaroslaw [1]

Answer:

The answer to your question is below

Explanation:

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Covalent polar bond: is a covalent bond between 2 elements of different elements, for example: hydrogen and chlorine or nitrogen, they are polar because on of the element that form it is smaller than the other one, then a partial positive and a partial negative charge is formed.

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