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RideAnS [48]
3 years ago
13

Please Help! 30 PTS. for correct answer and best explanation!

Chemistry
2 answers:
MaRussiya [10]3 years ago
8 0

Answer:

\huge \boxed{\mathrm{CH_4+ 2O_2 \Rightarrow CO_2 +2 H_2O}}

\rule[225]{225}{2}

Explanation:

\sf CH_4+ O_2 \Rightarrow CO_2 + H_2O

Balancing the Hydrogen atoms on the right side,

\sf CH_4+ O_2 \Rightarrow CO_2 +2 H_2O

Balancing the Oxygen atoms on the left side,

\sf CH_4+ 2O_2 \Rightarrow CO_2 +2 H_2O

In a balanced equation, the product side and the reactant side must have the same mass of matter, since matter cannot be destroyed or created according to the law.

\rule[225]{225}{2}

irakobra [83]3 years ago
6 0

Look kid, this question has been up for 17 hours think its time to let it go......... hoped i helped. ✔verified✔

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=> x = 18 g of glucose * 1 liter of solution / 180 g of glucose = 0.1 liter of solution.


If you assume that the 18 grams of glucose does not apport volume to the solution but that the volume of the solution is the same volumen of water added (which is the best assumption you can do given that you do not know the how much the 18 g of glucose affect the volume of the solution) then you should add 0.1 liter of water.

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1826.5g of methanol (CH3OH), molar mass = 32.0 g/mol is added to 735 g of water, what is the molality of the methane 0.0348 m 1.
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Answer:

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