B) To remove inorganic material.
This is an incomplete question, here is a complete question.
Determine the specific heat of a material if a 35 g sample absorbed 96 J as it was heated from 293 K to 313 K.
Answer : The specific heat of a material is, 0.137 J/g.K
Explanation :
Formula used to calculate the specific heat of a material is:
where,
q = heat absorbed = 96 J
m = mass of sample = 35 g
c = specific heat capacity of material = ?
= initial temperature = 293 K
= final temperature = 313 K
Now put all the given values in the above formula, we get:
Therefore, the specific heat of a material is, 0.137 J/g.K
Answer:
See below!
Explanation:
Solids have a definite mass, a definite shape, and a definite volume. They are not compressible and are the most tightly packed together.
Liquids have definite mass and definite volume. Liquids take up the shape of the container and are not compressible. They are slightly packed together but are allowed to move freely.
The answer is: volume of ammonia gas is 7.4 L.
Chemical reaction: 6NO + 4NH₃ → 5N₂ + 6H₂O.
m(NO) = 15 g; mass of nitrogen(II) oxide.
M(NO) = 30 g/mol; molar mass of nitrogen(II) oxide.
V(NH₃) = ?
n(NO) = 15 g ÷ 30 g/mol.
n(NO) = 0.5 mol; amount of nitrogen(II) oxide.
From chemical reaction: n(NO) : n(NH₃) = 6 : 4.
0.5 mol : n(NH₃) = 6 : 4.
n(NH₃) = 0.33 mol; amount of ammonia.
Vm = 22.4 L/mol; molar volume at STP.
V(NH₃) = 0.33 mol · 22.4 L/mol..
V(NH₃) = 7.4 L.
