Answer:
1x10⁻⁴ moles of Cl⁻ in NaCl solution
2x10⁻⁴ moles of Cl⁻ in MgCl₂ solution
3x10⁻⁴ moles of Cl⁻ in AlCl₃ solution
Explanation:
Let's produce the reactions of each salt
NaCl → Na⁺ + Cl⁻
0.1 m 0.1m
MgCl₂ → Mg²⁺ + 2Cl⁻
0.1m 0.2m
AlCl₃ → Al³⁺ + 3Cl⁻
0.1 m 0.3m
0.1, 0.2 and 0.3 are the moles of each chloride in each solution and this moles are added to one liter of solvent.
1 L = 1000mL
Let's prepare the rule of three for each
1000 mL ____ 0.1 m ____ 0.2 m _____ 0.3m
1 mL______ 1x10⁻⁴ m ___ 2x10⁻⁴ m _____ 3x10⁻⁴ m
Answer:
Physical=Ripping
Chemical=Burning
Explanation:
I may be wrong. But I would say these are the answers.
Answer : The enthalpy change for converting 1 mole of ice at
to water at
is, 7.712 KJ
Solution :
Process involved in the calculation of enthalpy change :

Now we have to calculate the enthalpy change.
![\Delta H=[m\times c_{ice}\times (T_2-T_1)]+\Delta H_{fusion}+[m\times c_{water}\times (T_3-T_2)]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5Bm%5Ctimes%20c_%7Bice%7D%5Ctimes%20%28T_2-T_1%29%5D%2B%5CDelta%20H_%7Bfusion%7D%2B%5Bm%5Ctimes%20c_%7Bwater%7D%5Ctimes%20%28T_3-T_2%29%5D)
where,
= enthalpy change
m = mass of water = 
= specific heat of ice = 2.09 J/gk
= specific heat of water = 4.18 J/gk
= enthalpy change for fusion = 6.01 KJ/mole = 0.00601 J/mole
conversion : 
= initial temperature of ice = 
= final temperature of ice = 
= initial temperature of water = 
= final temperature of water = 
Now put all the given values in the above expression, we get
![\Delta H=[18g\times 2.09J/gK\times (273-248)k]+0.00601J+[18g\times 4.18J/gK\times (363-273)k]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5B18g%5Ctimes%202.09J%2FgK%5Ctimes%20%28273-248%29k%5D%2B0.00601J%2B%5B18g%5Ctimes%204.18J%2FgK%5Ctimes%20%28363-273%29k%5D)
(1 KJ = 1000 J)
Therefore, the enthalpy change for converting 1 mole of ice at
to water at
is, 7.712 KJ
Methanol or <span>methyl alcohol</span>
Answer:
The mass of a sample of iron that has had 300 J applied to it and heats up from 20 degrees Celsius to 40 degrees Celsius is 32.61 grams.
Explanation:
Calorimetry is the measurement and calculation of the measurement of heat changes exchanged by a body or a system produced in physical and chemical processes.
The sensible heat of a body is the amount of heat received or transferred by a body to produce a change in temperature but without a change in physical state.
The sensible heat in a constant pressure is calculated by:
Q = c * m * ΔT
where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c, and where ΔT is the temperature variation (ΔT=Tfinal - Tinitial)
In this case:
- c= 0.46

- m= ?
- Tfinal= 40 C
- Tinitial= 20 C
Replacing:
300 J= 0.46
* m* (40 - 20) C
Solving:
300 J= 0.46
* m* 20 C

m= 32.61 g