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3 years ago

6

A car is traveling in a race. The car went from the initial velocity of 35 m/s to the final velocity of 6 m/s in 5 seco

1 answer:

ddd [48]3 years ago

7 0

Answer:

Explanation:

Acceleration = a change in velocity / a change in time

Acceleration = ( final velocity - initial velocity) / a change in time

Acceleration = (6m/s - 35 m/s ) / 5 s

= (-29 m/s) /( 5 s)

= - 5.8 m/s^^2

Remember Significant Figures

- 6 m/s^2

P.S I have no idea why the answers say m/s because acceleration is m/s^2.

:)

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What wavelength of radiation has photons of energy 2.87×x10−18 j?

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The energy of a photon is given by
$E=hf$
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Given the relationship between the frequency f, the wavelength $\lambda$ and the speed of light c for an electromagnetic wave:
$f= \frac{c}{\lambda}$
we can rewrite the energy of the photon as
$\lambda = \frac{hc}{E}$
and by substituting $h=6.6 \cdot 10^{-34 J}$ , $c=3 \cdot 10^8 m/s$ and $E=2.87 \cdot 10^{-18}J$ , we get the wavelength of the photon:
$\lambda = \frac{hc}{E}=6.9 \cdot 10^{-8} m = 69 nm$

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ValentinkaMS [17]

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Assume this field is generated by a point charge of Q = 5 × 10-9 C. How far away is this charge located? Give your answer in met

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3 years ago

A 97.6-kg baseball player slides into second base. The coefficient of kinetic friction between the player and the ground is μk =

Mila [183]

Answer:

$v=6.65m/sec$

Explanation:

From the Question we are told that:

Mass $m=97.6$

Coefficient of kinetic friction $\mu k=0.555$

Generally the equation for Frictional force is mathematically given by

$F=\mu mg$

$F=0.555*97.6*9.8$

$F=531.388N$

Generally the Newton's equation for Acceleration due to Friction force is mathematically given by

$a_f=-\mu g$

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Therefore

$v=u-at$

$v=0+5.45*1.22$

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3 years ago