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anyanavicka [17]
3 years ago
7

A 97.6-kg baseball player slides into second base. The coefficient of kinetic friction between the player and the ground is μk =

0.555.
(a) What is the magnitude of the frictional force?
(b) If the player comes to rest after 1.22 s, what is his initial speed?
Physics
1 answer:
Mila [183]3 years ago
4 0

Answer:

v=6.65m/sec

Explanation:

From the Question we are told that:

Mass m=97.6

Coefficient of kinetic friction  \mu k=0.555

Generally the equation for Frictional force is mathematically given by

 F=\mu mg

 F=0.555*97.6*9.8

 F=531.388N

Generally the  Newton's equation for Acceleration due to Friction force is mathematically given by

 a_f=-\mu g

 a_f=-0.555 *9.81

 a_f=-54455m/sec^2

Therefore

 v=u-at

 v=0+5.45*1.22

 v=6.65m/sec

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If the second harmonic of a certain string is 42 Hz, what is the fundamental frequency of the string?
sdas [7]
Data:
f_{2} = 42 Hz
n (Wave node)
V (Wave belly) 
L (Wave length)
<span>The number of bells is equal to the number of the harmonic emitted by the string.
</span>
f_{n} =  \frac{nV}{2L}

Wire 2 → 2º Harmonic → n = 2

f_{n} = \frac{nV}{2L}
f_{2} = \frac{2V}{2L} &#10;
2V =  f_{2} *2L
V =  \frac{ f_{2}*2L }{2}
V =  \frac{42*2L}{2}
V =  \frac{84L}{2}
V = 42L

Wire 1 → 1º Harmonic or Fundamental rope → n = 1


f_{n} = \frac{nV}{2L}
f_{1} = \frac{1V}{2L}
f_{1} =  \frac{V}{2L}

If, We have:
V = 42L
Soon:
f_{1} = \frac{V}{2L}
f_{1} = \frac{42L}{2L}
\boxed{f_{1} = 21 Hz}

Answer:

<span>The fundamental frequency of the string:
</span>21 Hz

7 0
3 years ago
Read 2 more answers
The driver of a 1000 kg car traveling at a speed of 16.7 m/s applies the brakes. If the brakes provide a force of - 8000 N to st
RSB [31]

Answer:

Given:

m=1000kg

u= 16.7m/s

v=0m/s

F=8000N

Required:

s=?

Solution:

F=m × a

8000N=1000kg × a

a=8m/s^2

Since it decelerate a= -8m/s^2

v^2 = u^2 + 2as

s=v^2 - u^2 / 2a

s= 0 - (16.7m/s)^2 / 2 × -8m/s^2

s= -278.89/-16

s= 17.43m

The car travels approximately 17.43m before it stops

Please like and follow me

6 0
2 years ago
The collision between a hammer and a nail can be considered to be approximately elastic. estimate the kinetic energy acquired by
Setler [38]

Here we can use momentum conservation as in this type of collision there is no external force on it

m_1v_{1i} + m_2v_{2i} = m_1 v_{1f} + m_2v_{2f}

now here we can say

m_1 = 10 g

v_{1i} = 0

m_2 = 550 g

v_{2i} = 3.5 m/s

now here we can say

10*0 + 550 * 3.5 = 10 v_{1f} + 550 v_{2f}

192.5 = v_{1f} + 55 v_{2f}

now by coefficient of restitution

for elastic collision we know that e = 1

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now by solving the two equation

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v_{2f} = 3.375 m/s

also we know that

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so final speed of the nail is 6.875 m/s


6 0
2 years ago
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A molecular cloud fragments as it collapses because Choose one: A. the interstellar wind is stronger in some places than others.
kondaur [170]

The cause for a molecular cloud forming fragments when it collapses is indicated correctly by option D. density variations from place to place grow larger as the cloud collapses.

Molecular cloud:

A molecular cloud, also known as a stellar nursery, is a specific kind of interstellar cloud, whose density and size allow the development of molecules, absorption nebulae, and H II regions. In contrast, some regions of the interstellar medium mostly consist of ionized gas.

Molecular clouds are cold, dense areas of space where stars form. The cloud collapses into a proto-star when the gravitational force pulling it in outweighs the internal pressure pushing it in.

When a molecular cloud collapses, it is observed that the density varies from place to place with the variation increasing with collapse. As a result, the collapse is characterized by fragmentation of the cloud.

Thus the correct option is: D. density variations from place to place grow larger as the cloud collapses.

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6 0
1 year ago
Many people drink 2 cans of coke each day. If each can has 39 grams of sugar, how many pounds of sugar is consumed each week? Gi
trasher [3.6K]

Answer:

1.20372

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