Answer:
1) Acceleration of player is 7.8125 .
2) Constant speed of player is 12.5 m/s.
Explanation:
Let the acceleration of the player by 'a' and let he complete the initial 10 meters in time
The initial 10 meters are case of uniformly accelerated motion and hence we can relate the above quantities using second equation of kinematics as
now since the player starts from rest hence u = 0 thus the equation can be written as
The speed the player reaches after time is obtained using first equation of kinematics as
Since the total distance traveled by the player is 40 meters hence the total time of trip is 4 seconds hence we infer that he covers 30 meters of distance at a constant speed in time of seconds
Hence we can write
Solving equation i and ii we get
from equation 'i' we obtain
Using this in equation 'ii' we get
Thus constant speed equals