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anzhelika [568]
2 years ago
8

Why dose bob not let humans touch him one and only Ivan

Engineering
1 answer:
gogolik [260]2 years ago
8 0
Sorry man i don’t know sorry
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A car is moving at 68 miles per hour. The kinetic energy of that car is 5 × 10 5 J.How much energy does the same car have when i
Blababa [14]

Answer:

The car has an energy of 1.017 × 10⁵ J when it moves at 97 miles per hour

Explanation:

Given the data in the question;

Initial velocity v₁ = 68 miles per hour = 30.398 meter per seconds

let mass of the car be m

kinetic energy of that car is 5 × 10⁵ J

so

E₁ = \frac{1}{2}mv²

we substitute

5 × 10⁵  = \frac{1}{2} × m × ( 30.398 )²

5 × 10⁵  = \frac{1}{2} × m × ( 30.398 )²

5 × 10⁵ = m × 462.019

m =  5 × 10⁵ / 462.019

m = 1082.2065 kg

Now, Also given that; v₂ = 97 miles per hour = 43.362 meter per seconds

E₂ = \frac{1}{2}mv₂²

we substitute

E₂ = \frac{1}{2} × 1082.2065 × ( 43.362 )²

E₂ = \frac{1}{2} × 1082.2065 × 1880.263

E₂ = 1.017 × 10⁵ J

Therefore, The car has an energy of 1.017 × 10⁵ J when it moves at 97 miles per hour

6 0
3 years ago
What is ductile to brittle transition temperature (DBTT)?
vova2212 [387]

Answer: The answer is given below

Explanation:

Ductile to brittle transition temperature (DBTT) is the temperature when there is a pronounced reduction in the ability of a material to absorb force without being fractured.

It shuld be noted that when this happens, the material transitions from ductile to brittle which is known as ductile to brittle transition temperature(DBTT).

DBTT

7 0
3 years ago
Q1: The first option should always be to get out safely (RUN)
nekit [7.7K]

Answer:

Q1 true

Q2 true

And other I am confuse

6 0
3 years ago
Ground effect is felt at a height that is equal to the plane's wingspan.<br> True or False
Oliga [24]

Answer:

True

Explanation:

7 0
3 years ago
A 993-kg car starts from rest at the bottom of a drive way and has a speed of 3.00 m/s at a point where the drive way has risen
tino4ka555 [31]

Answer:

13177.34 J

Explanation:

Work done = force × distance

work done by the engine = kinetic energy + potential energy + work done friction

kinetic energy due to the car's speed = 1/2mv² = 4468.5 J

potential energy due to the height = mgh = 993 kg × 9.8 m/s² × 0.6 m = 5838.84 J

work done by friction = 2870 J

work done by engine = 5838.84 J + 2870 J + 4468.5 J = 13177.34 J

7 0
3 years ago
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