Answer:
1) For the swung puck tied to the string that has a mass m₁ and having another mass m₂ attached to the string that passes through a hole in the table, such that m₂ > m₁
The swung puck rotating on the table is kept in the circular motion on the table by the centripetal force acting towards the center of its rotation along the string, which is given by the amount the weight of m₂ exceeds m₁, in the same way a planet moving around the Sun is kept in its orbit by the gravitational attraction between the planet and the Sun.
2) i) The forces acting on the puck are;
a) The centripetal force in the string, acting inward, towards the center of rotation provided by the weight of m₂
b) The centrifugal force of the puck, acting outward, tending to continue its motion in a straight line
ii) The forces acting on the planet are;
a) The force of gravitational attraction between the planet and the Sun, acting towards the Sun, such that, the planet revolves around the Sun
b) The centrifugal force of the planet, acting outward, tending to move in a linear or straight path
Explanation:
Answer:
118.166 volt
Explanation:
We have given number of turns N =345
Sides of the rectangular coils is 12 cm =0.12 m
So area A =0.12×0.12=0.0144 
Magnetic field B =0.45 T
Angular speed =505 rpm
Speed in rad/sec 
The emf is given by 
For maximum emf sinwt =1
So 
B damage the protective layers of the artery walls, which can intimately lead to heart disease.
Answer:
Average velocity = 30 miles per hour
Explanation:
Given that
Velocity for uphill = 20 miles per hour
Velocity for downhill = 60 miles per hour
We know that
Distance = Velocity x time
Total distance = Average velocity x total time
Lets take distance from home to school is s
Time taken from home to school= s/20 hr
Time taken from school to home= s/60 hr
Total time =s/20+s/60
Total distance = Average velocity x total time
s + s = Average velocity x (s/20+s/60)
So average velocity = 30 miles per hour
Answer:
D
The answer cannot be found until it is known whether q is greater than, less than, or equal to 45°.
Explanation:
Since block moves with constant speed
So, frictional force
f = FCosq
Work done by friction
W = - fd
W = - fd Cos q
The answer may be greater or less than - fdSinq. It depends on the value of q which is less than, or equal to 45°.
