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4 years ago

What is a circuit that only has one loop??

Physics

1 answer:

larisa86 [58]4 years ago

6 0

Series :) is the answer

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Whích phase change is the result of particles moving more quickly? (2 points)

sdas [7]

Answer:

liquid to gas

Explanation:

let me know if this helps

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3 years ago

An airplane flies 1,592 miles east from Phoenix Arizona, to Atlanta,Georgia,in 3.68 hours. What is the average velocity of the a

Fudgin [204]

Answer:

The average velocity would be 217 m/s.

Explanation:

Average velocity is calculated by v(avg)=final velocity+inital velocity over 2

Displacement is the change in position (vector)

Velocity is calculated by s= d/t distance/time

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4 years ago

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Conversion of one form of energy into another form is

Artist 52 [7]

Answer: energy transformation

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3 years ago

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A car travels with a constant velocity of 45km/hr for 20 sec. What distance does it cover

Flauer [41]

Explanation:

This is simple.

Convert the speed of 45km/h to metres per second (m/s):

45 * 1000m = 45000m per hour.

1 hour = 60 seconds * 60 minutes = 3600 seconds.

45000m/h / 3600 = 12.5m/s

(A quicker way is just to divide by 3.6)

So in 20 seconds it would cover:

12.5m/s * 20s = 250m.

A car travelling at 45km/h would travel 250 metres in 20s.

6 0

3 years ago

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A car covers 72 kilometers in the first hour of its journey. In the next hour, it covers 90 kilometers. What is the amount of wo

Nina [5.8K]

The work done is $2.8125 \times 10^{5} \mathrm{J}$

Work Done = Change in Kinetic Energy (ΔKE)

<u>Explanation</u>

In first 1 hour it travels 72 km

So, Velocity = $\frac{\text { distance }}{\text { time }}=\frac{72}{1} k m / h=72 \mathrm{km} / \mathrm{h}=\frac{72000}{3600} \mathrm{m} / \mathrm{s}=20 \mathrm{m} / \mathrm{s}$

or, Initial Velocity (u) = 20 m/s

Similarly for the next hour it covers 90 km

So, Velocity = $\frac{\text { distance }}{\text { time }}=\frac{90}{1} k m / h=90 \mathrm{km} / \mathrm{h}=\frac{90000}{3600} \mathrm{m} / \mathrm{s}=25 \mathrm{m} / \mathrm{s}$

or, Final Velocity (v) = 20 m/s

Work done = Change in Kinetic Energy (ΔKE)

Work done = ΔKE = $\frac{1}{2} m v^{2}-\frac{1}{2} m u^{2}$

ΔKE = $\frac{1}{2} m\left(v^{2}-u^{2}\right)=\frac{1}{2} \times\left(2.5 \times 10^{3}\right) \times\left(25^{2}-20^{2}\right)$

= $\frac{2500 \times(625-400)}{2}=\frac{2500 \times 225}{2}=\frac{562500}{2}$ = 281250 joule

= $2.8125 \times 10^{5} \mathrm{J}$

4 0

3 years ago