Lithium Chloride releases 37 kJ of energy per mole when dissolved in water.
Energy released = 0.25 x 37
= 9.25 kJ
= 9,250 J
Temperature change of water may be calculated using
ΔH = mCpΔT
Cp = 4.18 J/g
ΔT = 9,250 / (200 x 4.18)
ΔT = 11.1 °C
Answer:
The resultant electric force is 14.8N to the right.
Explanation:
Since the three charges aren't in the same line, we have to break down the force in components. First, we need to know the distance from the third charge to the other ones. That is made using the Pythagorean Theorem. As the figure is symmetric with respect to the x-axis, the two distances are the same:

Now, we use the Coulomb's Law to obtain the magnitude of the individual forces caused by each charge on the third charge:

For the same reason the distances are the same, the magnitude of the forces are the same:

So, to get the resultant force, we have to break down this forces in components. To do this, we need their angles with respect to the x-axis. Let θ₁ and θ₂ be these angles, respectively. Then, we calculate them using trigonometry:

Now, we calculate the components of the forces:

Evidently, the y-components cancel out, and the resultant electric force on the third charge is
along the x-axis (to the right, because it's positive).
Transform boundary
is the answer from stemscopes
Answer:
The number of electrons transferred from one ball to the other is 2.06 x 10¹² electrons
Explanation:
Given;
magnitude of the attractive force, F = 17 mN = 0.017 N
distance between the two objects, r = 24 cm = 0.24 m
The attractive force is given by Coulomb's law;

The charge of 1 electron = 1.602 x 10⁻¹⁹ C
n(1.602 x 10⁻¹⁹ C) = 3.298 x 10⁻⁷

Therefore, the number of electrons transferred from one ball to the other is 2.06 x 10¹² electrons
Answer:
200 km/h²
Explanation:
<em>Use the formula:</em>
acceleration = (final velocity - initial velocity) ÷ time taken
final velocity = 40 km/h
initial velocity = 30 km/h
time taken = 0.05 hours
<em>Substitute (plug in) the values into the equation:</em>
acceleration = (40 - 30) ÷ 0.05
acceleration = 10 ÷ 0.05
acceleration = 200 km/h²