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lianna [129]
3 years ago
11

How much kinetic energy is in a runner weighing 83 kg moving at a velocity of 16 m/s

Physics
1 answer:
ra1l [238]3 years ago
3 0

Answer:

10,624J

Explanation:

KE = 1/2 m*v²

KE = 1/2 83*16²

KE = 41.5*256

KE = 10,624J

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When 0.250 moles of licl are added to 200.0g of water in a constant pressure?
Mariana [72]
Lithium Chloride releases 37 kJ of energy per mole when dissolved in water.
Energy released = 0.25 x 37
= 9.25 kJ
= 9,250 J
Temperature change of water may be calculated using
ΔH = mCpΔT
Cp = 4.18 J/g

ΔT = 9,250 / (200 x 4.18)
ΔT = 11.1 °C
6 0
3 years ago
Two positive point charges, each of which has a charge of 2.5 × 10−9 C, are located at y = + 0.50m and y = − 0.50m. Find the mag
Salsk061 [2.6K]

Answer:

The resultant electric force is 14.8N to the right.

Explanation:

Since the three charges aren't in the same line, we have to break down the force in components. First, we need to know the distance from the third charge to the other ones. That is made using the Pythagorean Theorem. As the figure is symmetric with respect to the x-axis, the two distances are the same:

r=\sqrt{(0.50m)^{2}+(0.70m)^{2}}=0.86m

Now, we use the Coulomb's Law to obtain the magnitude of the individual forces caused by each charge on the third charge:

|F_{13}|=k\frac{q_1q_3}{r^{2}} \\\\|F_{13}|=(9*10^{9}Nm^{2}/C^{2})\frac{(2.5*10^{-9}C)(3.0*10^{-9}C)}{(0.86m)^{2}}\\\\|F_{13}|=9.1N

For the same reason the distances are the same, the magnitude of the forces are the same:

|F_{23}|=|F_{13}|=9.1N

So, to get the resultant force, we have to break down this forces in components. To do this, we need their angles with respect to the x-axis. Let θ₁ and θ₂ be these angles, respectively. Then, we calculate them using trigonometry:

\theta_1=\arctan(\frac{-0.50m}{0.70m})=-35.5\°\\\\\theta_2=\arctan(\frac{0.50m}{0.70m})=35.5\°

Now, we calculate the components of the forces:

F_{13}_x=F_{13}\cos\theta_1=9.1N\cos(-35.5\°)=7.4N\\\\F_{13}_y=F_{13}\sin\theta_1=9.1N\sin(-35.5\°)=-5.3N\\\\F_{23}_x=F_{23}\cos\theta_2=9.1N\cos(35.5\°)=7.4N\\\\F_{23}_y=F_{23}\sin\theta_2=9.1N\sin(35.5\°)=5.3N

Evidently, the y-components cancel out, and the resultant electric force on the third charge is 7.4N+7.4N=14.8N along the x-axis (to the right, because it's positive).

8 0
3 years ago
What will happen when you slide the sponges in different directions?
Ede4ka [16]

Transform boundary

is the answer from stemscopes

4 0
3 years ago
A charge Q is transferred from an initially uncharged plastic ball to an identical ball 24 cm away.The force of attraction is th
xxMikexx [17]

Answer:

The number of electrons transferred from one ball to the other is 2.06 x 10¹² electrons

Explanation:

Given;

magnitude of the attractive force, F = 17 mN = 0.017 N

distance between the two objects, r = 24 cm = 0.24 m

The attractive force is given by Coulomb's law;

F = \frac{1}{4\pi \epsilon _0} \times \frac{Q^2}{r^2} = \frac{kQ^2}{r^2} \\\\Q^2 = \frac{Fr^2}{k} \\\\Q = \sqrt{ \frac{Fr^2}{k}} \\\\Q = \sqrt{ \frac{(0.017)(0.24)^2}{9\times 10^9}} \\\\Q = 3.298 \times 10^{-7} \ C

The charge of 1 electron = 1.602 x 10⁻¹⁹ C

n(1.602 x 10⁻¹⁹ C) = 3.298 x 10⁻⁷

n = \frac{3.298 \times 10^{-7}}{1.602 \times 10^{-19}} = 2.06 \times 10^{12} \ electrons

Therefore, the number of electrons transferred from one ball to the other is 2.06 x 10¹² electrons

4 0
3 years ago
Lillie is running. She increases her initial speed of 30 km/h to 40 km/h so she can win the race. If she takes 0.05 hours to com
Rudiy27

Answer:

200 km/h²

Explanation:

<em>Use the formula:</em>

acceleration = (final velocity - initial velocity) ÷ time taken

final velocity = 40 km/h

initial velocity = 30 km/h

time taken = 0.05 hours

<em>Substitute (plug in) the values into the equation:</em>

acceleration = (40 - 30) ÷ 0.05

acceleration = 10 ÷ 0.05

acceleration = 200 km/h²

7 0
3 years ago
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