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netineya [11]
3 years ago
5

10. A force F S 1 of magnitude 6.00 units acts on an object at the ori- gin in a direction u 5 30.0° above the positive x axis (

Fig. P3.10). A second force F S 2 of magnitude 5.00 units acts on the object in the direction of the positive y axis. Find graphically the mag- nitude and direction of the resul- tant force F S 1 1 F S

Physics
1 answer:
MArishka [77]3 years ago
8 0

Answer:

The x component of the x axis is:   F_x = F_1\cos(30)=5\cos(30)= 4.33 u

The y component of the y axis is:  F_y =F_2+ F_1\sin(30)=6.00+5\sin(30)= 8.50 u

The magnitude is given by:  F = \sqrt{F_x+F_y}= 9.54 u

The direction is given by:  \theta = \tan^{-1}\frac{F_y}{F_x}= 63.0 ^\circ

See the graphical magnitude and direction below.

Explanation:

The x component of the x axis is:   F_x = F_1\cos(30)=5\cos(30)= 4.33 u

The y component of the y axis is:  F_y =F_2+ F_1\sin(30)=6.00+5\sin(30)= 8.50 u

The magnitude is given by:  F = \sqrt{F_x+F_y}= 9.54 u

The direction is given by:  \theta = \tan^{-1}\frac{F_y}{F_x}= 63.0 ^\circ

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There are three points in time we need to consider.  At point 0, the mango begins to fall from the tree.  At point 1, the mango reaches the top of the window.  At point 2, the mango reaches the bottom of the window.

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Solve for y₀ in the first equation and substitute into the second:

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