10. A force F S 1 of magnitude 6.00 units acts on an object at the ori- gin in a direction u 5 30.0° above the positive x axis (
Fig. P3.10). A second force F S 2 of magnitude 5.00 units acts on the object in the direction of the positive y axis. Find graphically the mag- nitude and direction of the resul- tant force F S 1 1 F S
1 answer:
Answer:
The x component of the x axis is:
The y component of the y axis is:
The magnitude is given by:
The direction is given by:
See the graphical magnitude and direction below.
Explanation:
The x component of the x axis is:
The y component of the y axis is:
The magnitude is given by:
The direction is given by:
You might be interested in
Answer:
<em>D. The total force on the particle with charge q is perpendicular to the bottom of the triangle.</em>
Explanation:
The image is shown below.
The force on the particle with charge q due to each charge Q =
we designate this force as N
Since the charges form an equilateral triangle, then, the forces due to each particle with charge Q on the particle with charge q act at an angle of 60° below the horizontal x-axis.
Resolving the forces on the particle, we have
for the x-component
= N cosine 60° + (-N cosine 60°) = 0
for the y-component
= -f sine 60° + (-f sine 60) = -2N sine 60° = -2N(0.866) = -1.732N
The above indicates that there is no resultant force in the x-axis, since it is equal to zero ( = 0).
The total force is seen to act only in the y-axis, since it only has a y-component equivalent to 1.732 times the force due to each of the Q particles on q.
<em>The total force on the particle with charge q is therefore perpendicular to the bottom of the triangle.</em>
