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3 years ago

A baseball with the mass of .8kg is thrown from rest to a velocity of 36 m/s in 0.1s.

Physics

1 answer:

Sati [7]3 years ago

6 0

A = (v-u)/t
v - speed
u - initial speed (zero here)
t - time taken
a=(36-0)/0.1 = 360 m/s^2

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Assume that the same amount of current passes through the electromagnets shown. Identify which electromagnet is stronger than th

hodyreva [135]

First electromagnet

Explanation:

The first electromagnet is the strongest and it is stronger than the given electromagnet above.

An electromagnet is a temporary magnet made by passing current through a wire wounded round an iron core or metallic core.

When current is passed through, the metal becomes magnetic.
The strength of the electromagnet depends on the number of coil round the metal core and also the intensity of current passed through it.
The higher the number of coils wounded round the metal core, the stronger the electromagnet that will be produced.
Also, the higher the intensity of electricity passed through the wire, the stronger it is.

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3 years ago

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A mass of 5kg accelerates at 3m/s/s, how much force was put on it?

goldfiish [28.3K]

Answer:

15N

Explanation:

According to Newton's Second Law of Motion

F = m*a

mass = m = 5Kg

acceleration = a = 3m/s^2

=> F = 5kg * 3m/s^2

=> F = 15 N

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3 years ago

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An apprentice bricklayer stabs 30cm long blocks on top of each other in such a way that 5cm of each block hangs over the lower b

NikAS [45]

Answer:

Explanation:The work done is twice as great for block B because it is moved twice the ... Equal forces are used to move blocks A and B across the floor. ... Does the normal force of the floor pushing upward on the block do any work? ... Suppose that the mass is halfway between one of the extreme points of its motion and the center point.

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2 years ago

Pluto’s diameter is approximately 2370 km, and the diameter of its satellite Charon is 1250 km. Although the distance varies, th

MissTica

Answer:

$r_{cm} = 2520.5 km$

Explanation:

As we know that mass is the product of volume and density

so we will have

$M = \rho V$

here we have

$M = \rho(\frac{4}{3}\pi r^3)$

so we will have

$\frac{M_p}{M_c} = (\frac{r_p}{r_c})^3$

so we will have

$\frac{M_p}{M_c} = (\frac{2370}{1250})^3$

$M_p = 6.81 M_c$

now let the position of Pluto is at origin so we have

$r_{cm} = \frac{M_p (0) + M_c(19700)}{M_p + M_c}$

$r_{cm} = \frac{19700}{\frac{M_p}{M_c} + 1}$

$r_{cm} = \frac{19700}{6.81 + 1}$

$r_{cm} = 2520.5 km$

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3 years ago

You need to fill a basketball with air to play with it. You know that your pump expels air at a velocity of 6 cm/s. You know tha

Scrat [10]

Answer:

The diameter of the needle is <u>4.675 cm</u>.

Explanation:

Given:

Volume flow rate is, $\dot V=103\ cm^3$

Velocity of air expelled by pump is, $v=6\ cm/s$

Let the area of the needle be 'A' cm² and the diameter be 'd' cm.

We know that, volume flow rate of the air expelled by pump is given as the product of the needle's area and velocity of air flowing through that area.

Therefore, volume flow rate is given as:

$\dot V=A\times v\\\\103=A\times 6\\\\6A=103\\\\A=\frac{103}{6}\ cm^2$

Now, considering the needle to be circular, area of the needle can be written as:

$A=\frac{\pi}{4}\times d^2\\\\\frac{103}{6}=\frac{\pi}{4}\times d^2\\\\d^2=\frac{103\times 4}{6\pi}\\\\d=\sqrt{\frac{103\times 4}{6\pi}}\\\\d=4.675\ cm$

Therefore, the diameter of the needle is 4.675 cm.

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3 years ago