3 years ago

Will give brainliest! how does an engineer use physical science?

Physics

1 answer:

pentagon [3]3 years ago

3 0

Answer: gravity, circuits

Explanation:

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The Magnifying power of a telescope is $M = 109.26$

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Radius of curvature R = 5.9 m = 590 cm

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Magnifying power of a telescope is given by,

$M = \frac{f_{objective} }{f_{eyepiece} }$

$M = \frac{295}{2.7}$

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therefore the Magnifying power of a telescope is $M = 109.26$

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