Answer:
Ag₂CrO₄(s) + H⁺(aq) ⟶ 2Ag⁺(aq) + HCrO₄⁻(aq)
Explanation:
Ag₂CrO₄(s) ⇌ 2Ag⁺(aq) + CrO₄²⁻(aq).
Silver chromate is the salt of a strong base (AgOH) and a weak acid (H₂CrO₄).
HCrO₄⁻ is an even weaker acid than H₂CrO₄, so CrO₄²⁻ is a strong base.
Any added H⁺ will immediately combine with the chromate ions according to the reaction
H⁺ + CrO₄²⁻ ⟶ HCrO₄⁻
thereby removing chromate ions from solution.
According to Le Châtelier's Principle, more silver chromate will dissolve to replace the chromate ions that the H⁺ removes.
The overall equation for the reaction is
Ag₂CrO₄(s) ⇌ 2Ag⁺(aq) + <em>CrO₄²⁻(aq)
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<u>H⁺(aq) + </u><em><u>CrO₄²⁻(aq)</u></em><u> ⟶ HCrO₄⁻(aq)
</u>
Ag₂CrO₄(s) + H⁺(aq) ⟶ 2Ag⁺(aq) + HCrO₄⁻(aq)
Answer:
dry
Explanation:
it will dry the hydrogen chloride to the ammonia
A. Strontium Phosphate
Solubility product constant is an equilibrium constant for the maximum amount of solute that can dissolve to form an aqueous solution. The value of the constant describes a solution which is saturated.
The greater the solubility product constant, the more soluble a solute is in the liquid. Consequently, the smaller the constant, the less soluble the solute is. The following list shows the solubility product constants of the given compounds in aqueous solutions at 298K in decreasing order:
Thallium Bromide - 3.71×10–6
Copper Iodide - 1.27×10<span>–12
</span>Silver Bromide - 5.35×10–13
Silver Arsenate - 1.03×10–22
Mercury Bromide - 6.40×10–23
Strontium Phosphate - 1×10–31
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The salt with the smallest solubility product constant is strontium phosphate, and therefore is the one which is least soluble in water.
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