All categories

2 years ago

to take off an aircraft carrier, 21000 kg jet needs to accelerate at 36.9 m/s ^2.how much force is required?

Physics

2 answers:

user100 [1]2 years ago

6 0

Force = mass times acceleration
F = 21000 x 36.9 = 774900
Therefore, 774900N force is required.

Dmitry [639]2 years ago

4 0

Answer:

774,9 kN

Explanation:

F = m * a

F = 21000 kg * 36.9 m/s ^2

F = 774 900 N = 774,9 kN

You might be interested in

I will fan and give 2 medals!!!!!!

Maksim231197 [3]

Corona

I. Rare gaseous envelope

II. Irregular pearly glow

III. Total solar eclipse

IV. Surrounds darkened moon

V. Caused by diffraction

Solar Prominence

I. loop shape

II. large bright gaseous

III. luminous hydrogen gas

IV. rises above chromospheres

V. anchored to surface (sun’s surface)

Solar Flare

I. Intense High-energy

II. Causes electromagnetic disruptions

III. In solar atmosphere

IV. Varies in brightness

V. Emits radiation

Sunspots

I. Surface dark spots

II. Strong magnetic fields

III. Solar magnetic storms

IV. Visible through telescope

V. Cooler than photospheres

I did this in class I got 100%

7 0

2 years ago

if the forces are moving in the same direction, ____ the forces. Please help i’m actually so confused!

jasenka [17]

Answer:

Explanation:

the directions may change

Or they will repel and become opposite sides

6 0

2 years ago

Which moment corresponds to the maximum potential energy of the system?

MissTica

6489 for the founding product

4 0

2 years ago

Two workers are sliding 290 kg crate across the floor. One worker pushes forward on the crate with a force of 430 N while the ot

m_a_m_a [10]

Answer:0.27

Explanation:

Given

One worker Pushes with force $F_1=430 N$

other Pulls it with a rope of rope $F_2=360 N$

mass of crate $m=290 kg$

both forces are horizontal and crate slides with a constant speed

Both forces are in the same direction so Friction will oppose the forces and will be equal in magnitude of sum of two forces because crate is moving with constant speed i.e. net force is zero on it

$f_r=F_1+F_2$

where $f_r$ is the friction force

$f_r=430+360$

$f_r=790 N$

$f_r=\mu N$

where $\mu$ is the coefficient of static friction

$N=mg$

$790=\mu 29\cdot 9.8$

$\mu =0.27$

6 0

3 years ago

What is the force of gravity for a 12 kg turkey? Please help asap

pogonyaev

Answer: 117.6N

Explanation:

By the second Newton's law, we know that:

F = m*a

F = force

m = mass

a = acceleration

We know that in the surface of the Earth, the gravitational acceleration is g = 9.8m/s^2.

Then we just can input that acceleration in the above equation, and also replace m by 12kg, and find that the force due the gravity is:

F = 12kg*9.8m/s^2 = 117.6N

7 0

2 years ago