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S_A_V [24]
2 years ago
5

to take off an aircraft carrier, 21000 kg jet needs to accelerate at 36.9 m/s ^2.how much force is required?

Physics
2 answers:
user100 [1]2 years ago
6 0
Force = mass times acceleration
F = 21000 x 36.9 = 774900
Therefore, 774900N force is required.
Dmitry [639]2 years ago
4 0

Answer:

774,9 kN

Explanation:

F = m * a

F =  21000 kg * 36.9 m/s ^2

F = 774 900 N = 774,9 kN

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2 years ago
Un engrane que gira con una velocidad de 20 rad/s, es acelerado durante 5 segundos hasta alcanzar una velocidad de 35 rad/s
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Answer:

a) La aceleración angular es: \alpha=2\: rad/s^{2}

b) El engranaje gira 125 radianes.

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Explanation:

a)

La aceleración angular se define como:

\alpha=\frac{\Delta \omega}{\Delta t}

Donde:

  • Δω es la diferencia de velocidad angular (en otras palabras ω(final)-ω(inicial))
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\alpha=\frac{35-25}{5}

\alpha=2\: rad/s^{2}

b)

El desplazamiento angular puede ser calculado usando la siguiente ecuación:

\theta=\theta_{i}+\omega_{i}t+\frac{1}{2}\alpha t^{2}

Aqui el angulo inicial es 0, por lo tanto.

\theta=20(5)+\frac{1}{2}(2)(5)^{2}

\theta=125\: rad

El engranaje gira 125 radianes.

c)

Lo que debemos hacer aquí es convertir radianes a revoluciones.

Recordemos que 2π rad = 1 rev

Entonces:

\theta=125\: rad \times \frac{1\: rev}{2\pi\: rad}=19.89\: rev

Por lo tanto el engranaje hara aproximadamente 20 revoluciones.

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6 0
3 years ago
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