Answer:
f = 55mm, h ’= -9.89 cm
f = 200 mm, h ’= 42.5 cm
Explanation:
For this exercise let's start by finding the distance to the image, using the equation of the constructor
where f is the focal length, p and q are the distances to the object and image, respectively
lens with f₁ = 55mm = 0.55cm
= 
= 1.718
q₁ = 0.582 m
lens with f₂ = 200mm = 2m
= 
= 0.4
q₂ = 2.5 m
the magnification of a lens is given by
m = 
h ’= 
let's calculate for each lens
f = 55mm
h '= - 0.582 / 10 1.7
h ’= 0.0989 m
h ’= -9.89 cm
f = 200 mm
h '= - 2.5 / 10 1.7
h ’= -0.425 m
h ’= 42.5 cm
The negative sign indicates that the image is real and inverted
Answer: Producers have the greatest amount of available energy.
When an organism eats another organism, it gains energy.
Explanation:
A food chain is a linear sequence of transfer of food and energy when one organism is eaten by the other organism. A food web is the interconnection of two or more food chains. This happens when one organism belong to one food chain also consume organisms of same food chain or other food chain. A food chain includes trophic levels on the basis of the mode of feeding of the living beings.
Among the options given, Producers have the greatest amount of available energy. and
When an organism eats another organism, it gains energy. are correct.
Producers are the organism which are capable of producing their food either through photosynthesis or chemosynthesis. They are present at the base level of the food chain. They consist of large amount of energy as compared to all the trophic levels in the food chain.
When one organism eats other organism it gains energy because of the assimilation and digestion of the organism as food.
Answer:
The electric potential at the midpoint between the two particles is 3.349 X 10⁻³ Volts
Explanation:
Electric potential is given as;
V = E*r
where;
E is the electric field strength, = kq/r²
V = ( kq/r²)*r
V = kq/r
k is coulomb's constant = 8.99 X 10⁹ Nm²/C²
q is the charge of the particles = 1.6 X 10⁻¹⁹ C
r is the distance between the particles = 859 nm
At midpoint, the distance = r/2 = 859nm/2 = 429.5 nm
V = (8.99 X 10⁹ * 1.6 X 10⁻¹⁹)/ (429.5 X 10⁻⁹)
V = 3.349 X 10⁻³ Volts
Therefore, the electric potential at the midpoint between the two particles is 3.349 X 10⁻³ Volts
