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4 years ago

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Physics

1 answer:

mojhsa [17]4 years ago

5 0

B. the distance the star is from Earth

Explanation:

The apparent magnitude of star is a function of its distance from the earth. It is one of the physical properties that is used to study a star.

The apparent magnitude of a star or other astronomical bodies is a measure of their brightness as seen from a location on the earth.

The apparent magnitude of a star depends on:

Distance of the star from the location on earth.
luminosity of the star
the particles along the part of the star and earth that cuts off the light the earth receives.

learn more:

Star luminosity brainly.com/question/9084808

#learnwithBrainly

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the impact time for a particular collision is 3.0 × 10-3 seconds and the impulse in the collision is 0.30 newton seconds. what i

Zanzabum

There are several information's already given in the question. The answer can be easily deduced using those information's.

Time = 3.0 * 10-3 seconds
Impulse = 0.30 newton
Then
Force = Impulse/Time
= 0.30/3.0 * 10-3
= 1 * 10^3 newtons.
I hope the above procedure is clear for you to understand and it has actually come to your great help.

3 0

4 years ago

Inside a car that was at 273 K, a bottle with a pressure at 100,000 pascals warms up to

Deffense [45]

Answer:

P2 = 128,205 pascal.

Explanation:

Given the following data;

Original Pressure, P1 = 100,000 pascals

Original Temperature, T1 = 273K

New Temperature, T2 = 350K

To find new pressure P2, we would use Gay Lussac' law.

Gay Lussac's law states that when the volume of an ideal gas is kept constant, the pressure of the gas is directly proportional to the absolute temperature of the gas.

Mathematically, Gay Lussac's law is given by;

$PT = K$

Where;

P represents pressure.

T represents temperature.

K is the constant of proportionality.

$\frac{P1}{T1} = \frac{P2}{T2}$

Making P2 as the subject formula, we have;

$P_{2}= \frac{P1}{T1} * T_{2}$

Substituting into the equation, we have;

$P_{2}= \frac{100000}{273} * 350$

$P_{2}= 366.3004* 350$

P2 = 128205.13 ≈ 128205 pascal.

Therefore, the pressure inside the hot water bottle is 128,205 pascal.

5 0

3 years ago

The temperature decreases 5°C in one hour and then decreases another 3°C in the next hour. Does this fit the definition of weath

Rus_ich [418]

Answer:

what is your age po? what

8 0

3 years ago

Two cars pass each other traveling at the same speed. one car has a constant velocity of 15.0 m/s, east. the other car has a con

GaryK [48]

The formula for calculating the distance at constant velocity is:

d = v * t

d = 15 t

The formula for distance at constant acceleration is:

d = v0 t + 0.5 a t^2

d = 15 t + 0.5 t^2

So after a sum distance of 164 m:

15 t + (15 t + 0.5 t^2) = 164

30 t + 0.5 t^2 = 164

t^2 + 60 t = 328

(t + 30)^2 = 328 + 30^2

t + 30 = ± 35.04

t = -65.04, 5.04

Since time cannot be negative, so the two cars are 164 m apart after about 5 seconds

8 0

3 years ago

The drawing shows a person (weight W = 588 N, L1 = 0.838 m, L2 = 0.398 m) doing push-ups. Find the normal force exerted by the f

zhenek [66]

Complete Question

The complete question is shown on the first uploaded image

Answer:

Force on each hand is 196.22 N

Force on each foot is 95.8 N

Explanation:

In order to get a better understanding of this question let us explain some concepts

Normal Force:

We can define normal force Fn as that type of force which makes a 90 degree angle with the surface on which it is exerted.

Torque:

We can define torque as the moment of forces that tends to produce or cause rotation

From the question we are given that

Weight of body is (W) = 584 N

The normal force on both hands (Ha) = ?

The normal force on both legs (Lg) = ?

Looking at the diagram the person is at equilibrium so

584 = Ha + Lg

an also this mean that torques acting on the body is balanced

So, 0.410 Ha = 0.840 Lg

Making Lg the subject of formula in the equation above we

Lg = 0.4881 Ha

Considering the first equation and replacing Lg with this recent equation we have

584 = Ha + 0.4881 Ha

Therefore Ha = 392.44 N

This value obtained is for both hands for each hand we divide by 2

Therefore we have for each hand $= 392.44/2$ =196.55 N

Since we have been able to get the force on both hands we can substitute it in to the equation where we made Lg the subject of formula and we have

Lg = 0.4881 × 392.44

= 191.22 N

The value above is the force on both legs to obtain the force on each leg we have

191.22/2 = 95.8 N.

8 0

4 years ago