Answer:81.235N
Explanation:
Work=88J
theta=10°
distance=1.1 meters
work=force x cos(theta) x distance
88=force x cos10 x 1.1 cos10=0.9848
88=force x 0.9848 x 1.1
88=force x 1.08328
Divide both sides by 1.08328
88/1.08328=(force x 1.08328)/1.08328
81.235=force
Force=81.235
Answer: A
Explanation: isotopes of the same thing element have the same number of protons in the nucleus but differ in the number of neutrons.
Answer:
Given:
Fundamental frequency: 470Hz
T1:310k,T2:315k
Calculating velocity
Recall v=(331m/s)✓[T1/273k)
V=331✓(310/273)
V1=331*(1.0656)=352.72m/s
V2=331✓(315/273)=355.5m/s
Fundamental frequency=4L
F2=F1(V2/V1)
F2=470(355.5/352.72)=474.4Hz
Beat=[F2-F1]=474.4-470=4.4Hz
Explanation:
Answer:
oxygen
Explanation:
as it is in the air it can't be depleted or used up
<span>You are given two cars, one in front of the other, that are traveling down the highway at 25 m/s. You are also given a frequency of 500 Hz of the car travelling behind it. You are asked what is the frequency heard by the driver of the lead car. This problem can be solved using the Doppler effect
sound frequency heard by the lead car = [(speed of sound + lead car velocity)/( speed of sound + behind car velocity)] * (sound of frequency of the behind car)
</span>sound frequency heard by the lead car = [(340 m/s + 25 m/s)/(340 m/s - 25 m/s)] * (500 Hz)
sound frequency heard by the lead car = 579 Hz
