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Anvisha [2.4K]
3 years ago
13

How to combine elements to make compounds?

Chemistry
1 answer:
zavuch27 [327]3 years ago
6 0
Elements combine<span> to </span>form<span> chemical </span>compounds<span> that are often divided into two categories. Metals often react with nonmetals to </span>form<span> ionic </span>compounds<span>. These </span>compounds<span> are composed of positive and negative ions formed by adding or subtracting electrons from neutral atoms and molecules.</span>
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On the window sill is a potted plant. The plant always seems to lean toward the window. Even though you turn its pot around ever
ICE Princess25 [194]

Answer:

because im trynna get these 5 points

Explanation:

mklnk.m

3 0
3 years ago
The mass of a 6.0 mL sample of kerosene is 4.92. The density of kerosene is
weqwewe [10]
4.92 grams / 6 mL = .82 grams / mL

<span>(A) 0.82 g/mL</span>
3 0
3 years ago
The atomic mass of 13C is 13.003355. Multiply the atomic mass of 13C by its abundance. Report the number to 8 significant digits
arsen [322]

Answer is: number is 0.14303691.

Carbon-13 (¹³C) is a stable isotope of carbon with mass number 13, it has six protons and seven neutrons.

Isotopes are chemical elements with same atomic number, but different mass number (different number of neutrons).

ω(¹³C) = 1.10% ÷ 100%.

ω(¹³C) = 0.0110; abundance of carbon-13 in nature.

m(¹³C) = 13.003355; the atomic mass of carbon-13.

ω(¹³C) · m(¹³C) = 0.0110 · 13.003355.

ω(¹³C) · m(¹³C) = 0.14303691.

4 0
3 years ago
What volume of a 3.5 m Hcl is required to completely neutralize 50.0ml of a 2.0 m naoh
Sauron [17]

Hey there!:

Molarity HCl = 3.5 M

Volume HCl = ?

Molarity NaOH = 2.0 M

Volume NaOH in liters = 50.0 mL / 1000 => 0.05 L

Number of moles NaOH:

n = M * V

n = 2.0 * 0.05

n = 0.1 moles of NaOH

Given the reaction:

HCl + NaOH = NaCl + H2O

1 mole HCl --------- 1 mole NaOH

1 mol HCl reacts with 1 mol NaOH , so moles NaOH = moles HCl

0.1 moles of NaOH = 0.1 moles of HCl

Therefore:

M( HCl ) = n / V

3.5 = 0.1 / V

V = 0.1 / 3.5

V = 0.029 L in mL :  0.029 * 1000 => 29.0 mL


hope that helps!


3 0
3 years ago
Assume a reaction takes place in a basic solution to form the given products: mno4-(aq) + cl-(aq) --------&gt; mno2(s) + cl2(g)
VARVARA [1.3K]
<span>To balance, we write it in its half reactions and balance the half reactions by adding H2O, OH-, H+ and electrons. We do as follows:

MnO4-(aq) + Cl-(aq) --------> MnO2(s) + Cl2(g) 


</span>2 (2H2O + MnO2 --> MnO4- + 4H+ 3e- )
<span>3 (2e- + Cl2 --> 2Cl- )
</span>
4H2O + 2MnO2 -----> 2MnO4- + 8H+ + 6e- 
<span>6e- + 3Cl2 -------> 6Cl- 
</span>----------------------------------------------------------------------
<span>4H2O + 2MnO2 + 3Cl2 --------> 2MnO4- + 6Cl- + 8H+ 

Since it is in a basic solution,

</span>8OH- + 2MnO2 + 3Cl2 -----> 2MnO4- + 6Cl- + 4H2O 



3 0
3 years ago
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