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Karo-lina-s [1.5K]
3 years ago
15

Suppose you are investigating how the amount of exercise a hamster gets affects how long the hamster lives. In order to control

the experiment, which of these should you do?
A. Give all the hamsters the exact same diet.
B. Compare how long hamsters live to how long mice live.
C. Have your friend do the same experiment with hamsters that you are doing.
D. Make all the hamsters run on a hamster wheel for the same amount of time.
Chemistry
2 answers:
ozzi3 years ago
4 0
Hello, to answer your question fully.

<span>D. Make all the hamsters run on a hamster wheel for the same amount of time.

 Because your doing the experiment on exercise not anything else 
 so keeping charts in a notebook and set a time on how long they were on it and how long you want them to be on it. 
   
                Signed by, Virtuoso Sargedog</span>

jekas [21]3 years ago
3 0

Answer:

D. Make all the hamsters run on a hamster wheel for the same amount of time.

Explanation:

Hello,

In this case, for you to study how the exercise affects the hamsters lifetime, you must put all the hamsters under the same exercising conditions, thus, by making all the hamsters run on a hamster wheel for the same amount of time, you can attain it.

Best regards.

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Una muestra de oxígeno ocupa 4.2 litros a 760 mm de hg . ¿ cual será el volumen del oxigeno a 415 mm de hg , si la temperatura p
ddd [48]

Teniendo en cuenta la ley de Boyle, el volumen del oxigeno a 415 mmHg, si la temperatura permanece constante, es 7,69 L.

Al aumentar el volumen, las partículas (átomos o moléculas) del gas tardan más en llegar a las paredes del recipiente y por lo tanto chocan menos veces por unidad de tiempo contra ellas. Esto significa que la presión será menor porque ésta representa la frecuencia de choques del gas contra las paredes.

De esta manera se relaciona la presión y el volumen, determinando la ley de Boyle que dice:

“El volumen ocupado por una determinada masa gaseosa a temperatura constante, es inversamente proporcional a la presión”

La ley de Boyle se expresa matemáticamente como:

P×V=k

Teniendo un estado inicial 1 y final 2, se cumple:

P₁×V₁= P₂×V₂

En este caso, se sabe que:

  • P₁= 760 mmHg
  • V₁= 4.2 L
  • P₂= 415 mmHg
  • V₂= ?

Reemplazando en la expresión matemática para la Ley de Boyle:

760 mmHg× 4.2 L= 415 mmHg× V₂

Resolviendo:

(760 mmHg× 4.2 L)÷ 415 mmHg= V₂

<u><em>7,69 L= V₂</em></u>

Finalmente, el volumen del oxigeno a 415 mmHg, si la temperatura permanece constante, es 7,69 L.

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5 0
2 years ago
Can someone tell me how to differentiate if a given salt is acidic, basic, or neutral?​
satela [25.4K]

\bold{\huge{\underline{ Solution }}}

<h3><u>Basic </u><u>Characteristic </u><u>of </u><u>acids </u></h3>

  • Acids are sour in taste
  • Acid turns blue litmus paper or solution into red litmus paper or solution
  • Acids are good conductor of electricity because it dissociate into cation in aqueous solution
  • Acids classified into edible acids and non edible acids. Non edible acids are very hazardous
  • Generally, All acids are soluble in water
  • Acids have PH smaller than 7

<u>Arrhenius </u><u>definition </u><u>of </u><u>acids </u><u>:</u><u>-</u>

According to Arrehinus,

  • Acids are those substances which when dissolve in water given H positive ions . Then, this hydrogen ions combine with water to form H30 + ions

<u>Second </u><u>definition </u><u>of </u><u>Acids </u><u>was </u><u>given </u><u>by </u><u>Bonsted </u><u>Lowry </u><u>:</u><u>-</u>

According to Bonsted Lowry

  • Acids are the proton donors that is when acids dissociate into water gives hydrogen ions that is H+ ions

<u>3rd </u><u>definition </u><u>was </u><u>given </u><u>by </u><u>Lewis </u>

According to Lewis

  • Acids are those substances which have the ability to accept a pair of electrons .

Example of Acids

  • HNO3 :- Nitric acid
  • H2SO4 :- Sulfuric acid
  • HCl :- Hydrochloric acid

<h3><u>Basic </u><u>characterists </u><u>of </u><u>bases </u></h3>

  • Bases are bitter in taste
  • Bases turns red litmus paper into blue litmus paper or solution
  • Bases are also good conductor of electricity because on dissociation it produces anion in aqueous solution
  • Bases are also good conductor of electricity
  • When bases are soluble in water then they are known as alkaline base
  • Bases have PH greater than 7

<u>Arrehinus definition of bases :-</u>

According to Arrehinus ,

  • Bases are those substances which when dissolve in water produce OH negative ions that is hydroxide ions

<u>Bonsted Lowry definition </u>

According to Bonsted Lowry

  • Bases are the proton donors as they produce OH negative ions in dissociation in aqueous solution

<u>Lewis </u><u>definition </u>

According to Lewis

  • Acids are those substances which have the ability to lose electrons that is they are electron donors.

Example of bases

  • Ca(OH)2 :- Calcium hydroxide
  • NaOH :- Sodium hydroxide
  • KOH :- Potassium hydroxide

[ Note :- There are so many Lewis acids and bases but they are not Arrhenius or Lowry acids or bases ]

<h3><u>Basic </u><u>characteristic </u><u>of </u><u>salt </u></h3>

  • Salts are the ionic compounds which are composed of acids and bases that cation and anion
  • Salts are generally found in oceans and seas in the forms of crystals
  • As they are composed of acids and bases so they are neutral in nature but the salt of strong acid or weak base is acidic in nature or vice versa
  • Salts are also good conductor of electricity as they form ionic bond
  • Generally, All salts are soluble in water.
  • The PH of common Salt is 7

Example of salts

  • NH4Cl :- Ammonium chloride
  • CuSO4 :- Copper sulphate
  • NaCl :- Sodium chloride
6 0
3 years ago
Are humans pro-karyotic or eukaryotic?
barxatty [35]

Answer:

eukaryotic

Explanation:

all human cells—including those found in the brain, the heart, the muscles, and so on—are also eukaryotic.

3 0
3 years ago
Oxygen gas can be prepared by heating potassium chlorate according to the following equation:2KClO3(s)Arrow.gif2KCl(s) + 3O2(g)T
Eduardwww [97]

Answer:

Moles of potassium chlorate reacted = 0.2529 moles

The amount of oxygen gas collected will be 12.8675 g

Explanation:

(a)

We are given:

Vapor pressure of water = 17.5 mmHg

Total vapor pressure = 748 mmHg

Vapor pressure of Oxygen gas = Total vapor pressure - Vapor pressure of water = (748 - 17.5) mmHg = 730.5 mmHg

To calculate the amount of Oxygen gas collected, we use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = 730.5 mmHg  

V = Volume of the gas = 9.49 L

T = Temperature of the gas = 20^oC=[20+273]K=293K

R = Gas constant = 62.3637\text{ L.mmHg }mol^{-1}K^{-1}

n = number of moles of oxygen gas = ?

Putting values in above equation, we get:

730.5mmHg\times 9.49L=n\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 293K\\\\n=\frac{730.5\times 9.49}{62.3637\times 293}=0.3794mol

According to the reaction shown below as:-

2KClO_3(s)\rightarrow 2KCl(s) +3O_2(g)

3 moles of oxygen gas are produced when 2 moles of potassium chlorate undergoes reaction.

So,

0.3794 mol of oxygen gas are produced when \frac{2}{3}\times 0.3794 moles of potassium chlorate undergoes reaction.

<u>Moles of potassium chlorate reacted = 0.2529 moles</u>

(b)

We are given:

Vapor pressure of water = 17.5 mmHg

Total vapor pressure = 753 mmHg

Vapor pressure of Oxygen gas = Total vapor pressure - Vapor pressure of water = (753 - 17.5) mmHg = 735.5 mmHg

To calculate the amount of Oxygen gas collected, we use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = 735.5 mmHg  

V = Volume of the gas = 9.99 L

T = Temperature of the gas = 20^oC=[20+273]K=293K

R = Gas constant = 62.3637\text{ L.mmHg }mol^{-1}K^{-1}

n = number of moles of oxygen gas = ?

Putting values in above equation, we get:

735.5mmHg\times 9.99L=n\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 293K\\\\n=\frac{735.5\times 9.99}{62.3637\times 293}=0.40211mol

Moles of Oxygen gas = 0.40211 moles

Molar mass of Oxygen gas = 32 g/mol

Putting values in above equation, we get:

0.037mol=\frac{\text{Mass of Oxygen gas}}{2g/mol}\\\\\text{Mass of Oxygen gas}=(0.40211mol\times 32g/mol)=12.8675g

<u>Hence, the amount of oxygen gas collected will be 12.8675 g</u>

5 0
3 years ago
what is the concentration (in %v/v)) of the following solutions? a. 25 mL of ethanol is diluted to a volume of 150 mL with water
fenix001 [56]
The symbol %v/v means percent by volume. Assuming there is no volume effects when these substances are mixed, we calculate as follows:

% v/v = (25 mL ethanol / 25 mL + 150 mL ) x 100
%v/v = 14.29 mL ethanol / mL solution

Hope this answers the question.
8 0
3 years ago
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