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Karo-lina-s [1.5K]
3 years ago
15

Suppose you are investigating how the amount of exercise a hamster gets affects how long the hamster lives. In order to control

the experiment, which of these should you do?
A. Give all the hamsters the exact same diet.
B. Compare how long hamsters live to how long mice live.
C. Have your friend do the same experiment with hamsters that you are doing.
D. Make all the hamsters run on a hamster wheel for the same amount of time.
Chemistry
2 answers:
ozzi3 years ago
4 0
Hello, to answer your question fully.

<span>D. Make all the hamsters run on a hamster wheel for the same amount of time.

 Because your doing the experiment on exercise not anything else 
 so keeping charts in a notebook and set a time on how long they were on it and how long you want them to be on it. 
   
                Signed by, Virtuoso Sargedog</span>

jekas [21]3 years ago
3 0

Answer:

D. Make all the hamsters run on a hamster wheel for the same amount of time.

Explanation:

Hello,

In this case, for you to study how the exercise affects the hamsters lifetime, you must put all the hamsters under the same exercising conditions, thus, by making all the hamsters run on a hamster wheel for the same amount of time, you can attain it.

Best regards.

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Following the instructions in your lab manual, you have titrated a 25.00 mL sample of 0.0100 M KIO3 with a solution of Na2S2O3 o
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<u>Answer:</u>

<u>For 1:</u> The amount of potassium iodate that were titrated is 2.5\times 10^{-4} moles

<u>For 2:</u> The amount of sodium thiosulfate required is 1.25\times 10^{-4} moles

<u>Explanation:</u>

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To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in L)}}

Molarity of KIO_3 solution = 0.0100 M

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Putting values in above equation, we get:

0.0100M=\frac{\text{Moles of }KIO_3\times 1000}{25}\\\\\text{Moles of }KIO_3=\frac{0.0100\times 25}{1000}=0.00025mol

Hence, the amount of potassium iodate that were titrated is 2.5\times 10^{-4} moles

  • <u>For 2:</u>

The chemical equation for the reaction of potassium iodate and sodium thiosulfate follows:

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By Stoichiometry of the reaction:

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So, 0.00025 moles of potassium iodate will react with = \frac{1}{2}\times 0.00025=0.000125mol of sodium thiosulfate

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