Answer:
The Anatomy of a Lens
Refraction by Lenses
Image Formation Revisited
Converging Lenses - Ray Diagrams
Converging Lenses - Object-Image Relations
Diverging Lenses - Ray Diagrams
Diverging Lenses - Object-Image Relations
The Mathematics of Lenses
Ray diagrams can be used to determine the image location, size, orientation and type of image formed of objects when placed at a given location in front of a lens. The use of these diagrams was demonstrated earlier in Lesson 5 for both converging and diverging lenses. Ray diagrams provide useful information about object-image relationships, yet fail to provide the information in a quantitative form. While a ray diagram may help one determine the approximate location and size of the image, it will not provide numerical information about image distance and image size. To obtain this type of numerical information, it is necessary to use the Lens Equation and the Magnification Equation. The lens equation expresses the quantitative relationship between the object distance (do), the image distance (di), and the focal length (f)
<span><span>Sand 5.0
</span><span>Loam 1.3
</span><span>Clay loam 0.8
</span><span>Silty clay 0.25
</span><span>Clay <span>0.05</span></span></span>
The board is 2.50m high.
Why?
We can calculate how high was the board applying the Law of Conservation of Mechanical Energy. This Law states that the mechanical energy (kinematic and potential) will be conserved during the motion.
It can be described with the following formula:
At the top of the boar, the kinetic energy is equal to 0.
At the water, the potential energy is equal to 0.
So,
Hence, we have that the board is 2.50m high.
Have a nice day!
Answer:
v=115 m/s
or
v=414 km/h
Explanation:
Given data
To find
Terminal velocity (in meters per second and kilometers per hour)
Solution
At terminal speed the weight equal the drag force
For speed in km/h(kilometers per hour)
To convert m/s to km/h you need to multiply the speed value by 3.6
