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3 years ago

Which of the following is not a way to make exercising on a cold day safer?

Physics

2 answers:

IRISSAK [1]3 years ago

4 0

Answer:

Explanation:

I think its D. because Tea during a cold workout isnt safe at all. Drinking tea while working out adds weight and you just simply dont need tea when working out.. Hope this helps man :)

dsp733 years ago

4 0

C. You shouldn't exercise while drinking hot tea because you can spill it and burn yourself especially while on a treadmill.

If this helped please mark me as brainliest!

$\left[\begin{array}{ccc}Thanks,\\JustSomeIdiot\end{array}\right]$

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If you stretch a rubber hose and pluck it, you can observe a pulse traveling up and down the hose.(i) What happens to the speed

Monica [59]

The thing that happens to the speed of the pulse when you stretch the hose more tightly is that it increases.

<h3>What is wage speed?</h3>

It should be noted that wave speed simply means the distance that a wave travels during a particular time.

It should be noted that higher tension leads to an increase in the speed of the wave.

Therefore, the thing that happens to the speed of the pulse when you stretch the hose more tightly is that it increases.

Learn more about speed on:

brainly.com/question/13943409

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4 0

1 year ago

A child kicks a ball horizontally with a speed of 4.8 m/s off a deck 3.5 m off the ground. How far, in meters, from the deck doe

Vesna [10]

Answer:

2.605m

Explanation:

Using the formula for calculating Range (distance travelled in horizontal direction)

Range R = U√2H/g

U is the speed = 4.8m/s

H is the maximum height = ?

g is the acc due to gravity = 9.8m/s²

R = 3.5m

Substitute into the formula and get H

3.5 = 4.8√2H/9.8

3.5/4.8 = √2H/9.8

0.7292 = √2H/9.8

square both sides

0.7292² = 2H/9.8

2H = 0.7292² * 9.8

2H = 5.21

H = 5.21/2

H = 2.605m

Hence the height of the ball from the ground is 2.605m

7 0

2 years ago

Can someone answer all of the questions?

Katyanochek1 [597]

Answer: -200

Explanation: is it math

8 0

2 years ago

Read 2 more answers

Two balls are dropped from rest and allowed to fall. If one ball is allowed to fall for 1 s and the other for 3 s compare the di

kirill115 [55]

The second ball traveled a greater distance when compared to the first ball because the second ball spent more time in motion.

The given parameters;

time of fall of the first ball, t = 1 s
time of fall of the second ball, t = 3 s

The distance traveled by each ball is calculated using the second equation of motion as shown below.

The distance traveled by the first ball is calculated as follows;

$h = u_0t + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\h = (0.5\times 9.8\times 1^2)\\\\h = 4.9 \ m$

The distance traveled by the second ball is calculated as follows;

$h = \frac{1}{2} gt^2\\\\h = (0.5\times 9.8\times 3^2)\\\\h = 44.1\ m$

Thus, the second ball traveled a greater distance because it spent more time in motion.

Learn more here:brainly.com/question/5868480

3 0

1 year ago

Suppose a clay model of a koala bear has a mass of 0.200 kg and slides on ice at a speed of 0.750 m/s. It runs into another clay

kaheart [24]

Answer:

0.278 m/s

Explanation:

We can answer the problem by using the law of conservation of momentum. In fact, the total momentum before the collision must be equal to the total momentum after the collision.

So we can write:

$mu=(m+M)v$

where

m = 0.200 kg is the mass of the koala bear

u = 0.750 m/s is the initial velocity of the koala bear

M = 0.350 kg is the mass of the other clay model

v is their final combined velocity

Solving the equation for v, we get

$v=\frac{mu}{m+M}=\frac{(0.200)(0.750)}{0.200+0.350}=0.278 m/s$

8 0

3 years ago