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MariettaO [177]
3 years ago
8

An electromagnetic wave is propagating towards the west. At a certain moment the direction of the magnetic field vector associat

ed with this wave points vertically up. The direction of the electric field vector of this wave options:
vertical and pointing down.
vertical and pointing up.
horizontal and pointing north.
horizontal and pointing south.
horizontal and pointing east.
Physics
1 answer:
ikadub [295]3 years ago
4 0

Answer:

Horizontal and pointing south.

Explanation:

The Poynting vector points in the direction of propagation (if the wave is a sinusoidal linearly polarized plane wave of fixed frequency, as it is in our case), and it's given by (all vectors):

S=E\times H

where H points in the same direction as B, the magnetic field. This means that E must point south, because the vectorial product of a vector pointing south by a vector pointing up gives a vector pointing west. This can be deduced by the right-hand rule: if our index finger is E and our middle finger is H, then the thumb is S.

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You are asked to design a retroreflector using two mirrors that will reflect a laser beam by 180 degrees independent of the inci
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Answer:

Consider the diagram. We are effectively being asked to prove that $\alpha=i_1$, for any value of $i_1$. Now, from trigonometry,

Explanation:

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3 years ago
What is a non-example of gravitational force?
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3 years ago
Read 2 more answers
A 39-foot ladder is leaning against a vertical wall. If the bottom of the ladder is being pulled away from the wall at the rate
Viefleur [7K]

Answer:

The rate of change of the area when the bottom of the ladder (denoted by b) is at 36 ft. from the wall is the following:

\frac{dA}{dt}|_{b=36}=-571.2\, ft^2/s

Explanation:

The Area of the triangle is given by A=h\times b where h=\sqrt{l^2-b^2} (by using the Pythagoras' Theorem) and b is the length of the base of the triangle or the distance between the bottom of the ladder and the wall.

The area is then

A=\sqrt{l^2-b^2}b

The rate of change of the area is given by its time derivative

\frac{dA}{dt}=\frac{d}{dt}\left(\sqrt{l^2-b^2}\cdot b\right)

\implies \frac{dA}{dt}=\frac{d}{dt}\left(\sqrt{l^2-b^2}\right)\cdot b+\frac{db}{dt}\cdot\sqrt{l^2-b^2}

\implies\frac{dA}{dt}=\frac{1}{2\sqrt{l^2-b^2}}\frac{d}{dt}(l^2-b^2)\cdot b+\sqrt{l^2-b^2}}\cdot \frac{db}{dt} Product rule

\implies\frac{dA}{dt}=-\frac{1}{2\sqrt{l^2-b^2}}\cdot 2\cdot b^2\cdot \frac{db}{dt}+\sqrt{l^2-b^2}}\cdot \frac{db}{dt} Chain rule

\implies\frac{dA}{dt}=-\frac{1}{\sqrt{l^2-b^2}}\cdot b^2\cdot \frac{db}{dt}+\sqrt{l^2-b^2}}\cdot \frac{db}{dt}

\implies\frac{dA}{dt}=\frac{db}{dt}\left(-\frac{1}{\sqrt{l^2-b^2}}\cdot b^2+\sqrt{l^2-b^2}}\right)

In here we can identify b=36\, ft, l=39 and \frac{db}{dt}=8\,ft/s.

The result is then

\frac{dA}{dt}=8\left(-\frac{1}{\sqrt{39^2-36^2}}\cdot 36^2+\sqrt{39^2-36^2}}\right)=-571.2\, ft^2/s

3 0
2 years ago
WHAT DOES THE EXPRESSION "EM" IN EM SPECTRUM REPRESENT
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EM stands for ElectroMagnetic.
4 0
3 years ago
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10. Calculate the kinetic energy of a running back that has a mass of 80 kg and
EastWind [94]

Answer:

The answer is

<h2>2560 J</h2>

Explanation:

The kinetic energy of an object given it's mass and velocity can be found by using the formula

KE =  \frac{1}{2} m {v}^{2}

where

m is the mass

v is the velocity

From the question

m = 80 kg

v = 8 m/s

The kinetic energy is

KE =  \frac{1}{2}  \times 80 \times  {8}^{2}  \\  = 40 \times 64

We have the final answer as

<h3>2560 J</h3>

Hope this helps you

5 0
2 years ago
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