By Newton's second law,
<em>n</em> + (-<em>w</em>) = 0
<em>p</em> + (-<em>f</em> ) = (20 kg) (2 m/s²)
where <em>n</em> is the magnitude of the normal force, <em>w</em> is the weight of the box, <em>p</em> is the magnitude of the applied force (<em>p</em> for <u>p</u>ush or <u>p</u>ull), and <em>f</em> is the magnitude of the friction force.
Calculate the weight of the box:
<em>w</em> = (20 kg) (9.80 m/s²) = 196 N
Then
<em>n</em> = <em>w</em> = 196 N
and
<em>f</em> = <em>µ</em> <em>n</em> = 0.5 (196 N) = 98 N
Now solve for <em>p</em> :
<em>p</em> - 98 N = 40 N
<em>p</em> = 138 N
Answer:
To measure the total current, the ammeter must be placed at position 1, as all the current in the circuit must pass through this wire, and ammeters are always connected in series. To measure the total voltage in the circuit, the voltmeter could be placed at either position 3 or position 4.
Explanation:
Answer:
I think it's carbohydrates
Explanation:
The energy from light causes a chemical reaction that breaks down the molecules of carbon dioxide and water and reorganizes them to make the sugar (glucose) and oxygen gas.
A)float
D)<span>density is greater than the weight of the object
</span>
Answer:
s = 11.46 m
Explanation:
Since, the reaction time is 0.75 s. Hence, the brakes shall be applied after this time. So, the car will start to slow down after covering a distance at the constant speed during this time. This distance can be given as follows:
s = vt
where,
s = distance covered by car before slowing down = ?
v = speed of car = (55 km/h)(1 h/3600 s)(1000 m/1 km) = 15.28 m/s
t = reaction time = 0.75 s
Therefore,
s = (15.28 m/s)(0.75 s)
<u>s = 11.46 m</u>
