<span>Answer: 6.1 g of Ca(NO₃)₂•4H₂O and 5.5 g of KIO₃
</span>
<span>Explanation:
</span>
1) Calculate the number of moles of <span>Ca(NO₃)₂ in 10.0 g
</span>
i) molar mass of <span>Ca(NO₃)₂ = 40.1 g/mol + 2x126.9 g/mol + 2x3x16.0 g/mol = 389.9 g/mol
</span>
<span>ii) Formula: number of moles = mass in grams / molar mass
</span>number of moles = 10.0 g / 389.9 g/mol = 0.02565 moles of Ca(NO₃)₂
<span>
</span><span>2) Write the chemical equation to state the mole ratio:</span>
<span />
<span>i) Ca(NO₃)2•4H₂O(s) + 2KIO₃(s) --> Ca(IO₃)₂(s) + 2KNO₃ + 4H₂O
</span>
ii) mole ratio: 1 mol Ca(NO₃)2•4H₂O(s) : 2 mol KIO₃(s) : 1 mol <span>Ca(IO₃)₂(s)
</span>
3) Use proportionality to find the actual number of moles
<span>
</span><span>i) </span>Ca(NO₃)₂•4H₂O(s)
1 mol <span>Ca(NO₃)₂•4H₂O(s) / 1 mol Ca(IO₃)₂ = x / 0.02565 mol Ca(IO₃)₂ => x = 0.02565 mol </span>Ca(NO₃)₂•4H₂O(s)
molar mass of <span><span>Ca(NO₃)₂•4H₂O(s)</span> = 40.0g/mol + 2x14.0g/mol + 2x3x16.0g/mol + 4x18.0g/mol = 236.0g/mol
</span>
<span>mass in grams = number of moles x molar mass = 0.02565 mol x 236.0 g/mol = 6.1 g
</span>ii) KIO₃
<span />
<span>1mol KIO₃/1molCa(IO₃)₂ = x / 0.02565 mol Ca(IO₃)₂ => x = 0.02565 mol KIO₃</span>
<span>molar mas of KIO₃ = 39.1 g/mol + 126.9 g/mol + 3x16.0 g/mol = 214.0 g/mol
</span>
mass in grams = 0.02565 mol x 214.0 g/mol = 5.5 g
Rate = k[A][B]
This means the rate is directly proportional to the concentration of A and B, i.e. first order in both.
So, if [A] doubles, and [B] stays the same, the rate will double.
If [B] doubles, and [A] stays the same, the rate will double.
If both [A] and [B] double, the rate will increase by 4 times.
You can see this mathematically from the rate law as follows:
Rate = k[2][2] = 4k and since k is constant, the rate will be 4x what it was when the [A] and [B] were each 1.
A. <span> Ionic—Magnesium will give 2 electrons to oxygen, and both will become ions.</span>
1. Given the following equation: N2 (g) + 3 H2 (g) ↔ 2NH3 (g) ΔH = -92 kJ/mol
a. this reaction is exothermic as ΔH is -ve
b. the equilibrium will shift 2 the left if nitrogen gas is removed
c. the equilibrium shift 2 the right if the temperature is lowered
d. the equilibrium shift 2 the left if ammonia (NH3) is added
e. principle of thermodynamic potential or Gibbs energy is used to answer B-D