Answer:
H-F> H-O> O-F
while H-H is nonpolar.
Explanation:
The bond is polar when electronegativity difference of both bonded atom is greater than 0.4.
Electronegativity values of O. F and H are
O = 3.4
H = 2.2
F = 3.98
For O-F
3.98 - 3.4 = 0.58
For H-F
3.98 - 2.2 = 1.78
For H-O
3.4 - 2.2 = 1.2
For H-H
2.2 -2.2 = 0
So H-H is nonpolar.
Answer:
where are the statements??
Explanation:
Three protons and three electrons. The protons are the plus signs because protons are positively charged, and the electrons are the minus signs because electrons are negatively charged. Also, the neutrons are the circles. Neutrons are negatively charged
So I set up the problem as follows:
Solve for X, and you should get 52g Solution
Answer:
C. 2O₃ ⇌ 3O₂
Explanation:
Kp is the equilibrium constant calculated from the partial pressures of a gas-phase reaction equation.
For a general gas-phase reaction aA + bB ⇌ nC + xD
the expression for the Kp = (pC)ⁿ(pD)ˣ / (pA)ᵃ(pB)ᵇ
where pA = partial pressure of A; pB = partial pressure of B; pC = partial pressure of C; pD = partial pressure of D
From the given reaction in equilibrium; N₂ + 3H₂ ⇌ 2NH₃
Kp = (pNH₃)² / (pN₂)¹ * (pH₂)³ = 4/7
(pNH₃)² / (pN₂)¹ * (pH₂)³ = (2)²/ (1)¹ * (3)³
Therefore, number of mole of reactants and products is equivalent to partial pressure.
A. 2SO₂ ⇌ O₂ + 2SO₃
pSO₂ = 2, pO₂ = 1, pSO₃ = 2,
Kp = 2²/ (2² * 1²) = 4/4 = 1
B. N₂O₄ ⇌ 2NO₂
pN₂O₄ = 1, pNO₂ = 2
Kp = 2²/1² = 4
C. 2O₃ ⇌ 3O₂
pO₃ = 2, pO₂ = 3
Kp = 3³/2² = 27/4
D. PCl₅ ⇌ PCl₃ + Cl₂
pPCl₅ = 1, pPCl₃ = 1, pCl₂ = 1
Kp = (1¹ * 1¹) / 1¹ = 1
