Answer: Attractive forces between particels
Explanation:
They can use them to find the age of fossils.
Answer:According to Boyle's Law, the volume of a gas is inversely proportional to the pressure of a gas. Therefore, increasing the volume has the same effect as decreasing the pressure. If the volume in which a gas reaction takes place is DECREASED, the reaction will shift toward the side with fewer moles of GAS.
Explanation:
A physical change is like freezing water and it turns into Ice.
Answer:
- 13.56 g of sodium chloride are theoretically yielded.
- Limiting reactant is copper (II) chloride and excess reactant is sodium nitrate.
- 0.50 g of sodium nitrate remain when the reaction stops.
- 92.9 % is the percent yield.
Explanation:
Hello!
In this case, according to the question, it is possible to set up the following chemical reaction:

Thus, we can first identify the limiting reactant by computing the yielded mass of sodium chloride, NaCl, by each reactant via stoichiometry:

Thus, we infer that copper (II) chloride is the limiting reactant as it yields the fewest grams of sodium chloride product. Moreover the formed grams of this product are 13.56 g. Then, we take 13.56 g of sodium chloride to compute the consumed mass sodium nitrate as it is in excess:

Therefore, the leftover of sodium nitrate is:

Finally, the percent yield is computed via:

Best regards!