The velocity, expressed in terms of ME, RE is given as
.
The maximum height that the rocket could reach if launched vertically is H = (¹/₂v₀²)/g.
<h3>Maximum height of the rocket</h3>
The maximum height reached by the rocket can be modeled using conservation of energy as shown below;
P.Ei + K.Ei = K.Ef + P.Ef

<h3>Maximum height when it is launched vertically</h3>
P.E = K.E
mgH = ¹/₂mv²
H = (¹/₂v₀²)/g
Learn more about conservation of energy here: brainly.com/question/166559
It should be true: electrons low from negative toward positive to negative toward positive because opposite charges attract each other.
I hope this was correct
Bohr, he invented the Bohr model which is the basis for the beginning of quantum physics.
Explanation:
The emf is equal to the work done on the charge per unit charge (ϵ=dWdq) when there is no current flowing. Since the unit for work is the joule and the unit for charge is the coulomb, the unit for emf is the volt (1V=1J/C).