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mart [117]
4 years ago
10

What affects sounds at their source? MENTION DOPPLER EFFECT AND VIBRATIONS

Physics
1 answer:
wel4 years ago
6 0

Answer:

Doppler effect, the apparent difference between the frequency at which sound or light waves leave a source and that at which they reach an observer, caused by relative motion of the observer and the wave source. This phenomenon is used in astronomical measurements, in Mössbauer effect studies, and in radar and modern navigation.

Explanation:

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Gravity is affected by the ______
Alla [95]

C is the right answer :)

C. mass of the objects and the distance between two objects

4 0
4 years ago
Read 2 more answers
Properties that change when the size of an object changes are called?
frozen [14]
<span>A physical change involves a change in physical properties. Examples of physical properties include melting, transition to a gas, change ofstrength, change of durability, changes to crystal form, textural change, shape, size, color, volume and density.b

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5 0
4 years ago
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What is the gauge pressure in Pascals inside a honey droplet of a 0.1 cm diameter? Assume that air is surrounding this droplet a
Vikki [24]

Answer:

The gauge pressure in Pascals inside a honey droplet is 416 Pa

Explanation:

Given;

diameter of the honey droplet, D = 0.1 cm

radius of the honey droplet, R = 0.05 cm = 0.0005 m

surface tension of honey, γ = 0.052 N/m

Apply Laplace's law for a spherical membrane with two surfaces

Gauge pressure =  P₁ - P₀ = 2 (2γ / r)

Where;

P₀ is the atmospheric pressure

Gauge pressure = 4γ / r

Gauge pressure = 4 (0.052) / (0.0005)

Gauge pressure = 416 Pa

Therefore, the gauge pressure in Pascals inside a honey droplet is 416 Pa

5 0
4 years ago
A student uses a stopwatch to measure the period of the pendulum of the Beverly clock in the corridor. His measurements are: (a)
Westkost [7]

Answer:

Reading is close to (b) 13.44 which is the best estimate of the period

Associated error, \Delta E =0.178 s

Given:

t_{a} = 13.54 s

t_{b} = 13.44 s

t_{c} = 13.89 s

t_{d} = 13.41 s

t_{e} = 13.17 s

t_{f} = 13.22 s

Solution:

1.The best estimate of the period can be calculated by the mean of the measurements and the one closest to the mean is the best estimate of the measurement:

Mean, \bar {x} = \fra{sum of all observations}{No. of observation}

Mean, \bar {x} = \frac{t_{a} + t_{b} + t_{c} +t_{d} + t_{e} + t_{f}}{6}

Mean, \bar {x} = \frac{13.54 + 13.44 + 13.89 + 13.41 + 13.17 + 13.22}{6}

Mean, \bar {x} = 13.445 s

It is close to 13.44 s

2. Associated error is given by:

\Delta E_{n} = |measured value - actual value|

\Delta E_{n} = |t_{n} - \bar {x}|

where

n = a, b,......, e

Now,

\Delta E_{a} = |t_{a} - \bar {x}| = |13.54 - 13.44| = 0.01

\Delta E_{b} = |t_{b} - \bar {x}| = |13.44 - 13.44| = 0.00

\Delta E_{c} = |t_{c} - \bar {x}| = |13.89 - 13.44| = 0.45

\Delta E_{d} = |t_{d} - \bar {x}| = |13.41 - 13.44| = 0.03

\Delta E_{e} = |t_{e} - \bar {x}| = |13.17 - 13.44| = 0.027

\Delta E_{f} = |t_{f} - \bar {x}| = |13.54 - 13.44| = 0.10

Mean Absolute Error, \Delta E = \frac{\Sigma E_{n}}{6}

\Delta E = \frac{0.01 + 0.00 + 0.45 + 0.03 +0.027 + 1.10}{6}

\Delta E =0.178 s

3. The assumption behind the estimation is population is considered to distributed normally.

6 0
3 years ago
An electrical device in which a long wire is wound into a succession of closely spaced loops around a n insulating core is calle
Iteru [2.4K]

Answer:

Solenoid I think.

Explanation:

6 0
3 years ago
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