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ValentinkaMS [17]
3 years ago
10

Zak, helping his mother rearrange the furniture in their living room, moves a 60 kg sofa 5.9 m with a constant force of 40 N. Wh

at is the work done by Zak on the sofa? Neglect friction. Answer in units of J
Physics
2 answers:
Valentin [98]3 years ago
5 0

Answer:

236 j

Explanation:

mass of sofa, m = 60 kg

distance, d = 5.9 m

force, F = 40 N

Work done is defined as the product of force applied on the body and the displacement in the position of the body in the direction of force.

W = F x d

W = 40 x 5.9

W = 236 J

Thus, the work done is 236 J.

Len [333]3 years ago
4 0

Answer:236 J

Explanation:

Given

Mass of sofa m=60 kg

Displacement s=5.9 m

Force F=40 N

neglecting Friction

Work done is given by

W=F\cdot s

W=F\cdot s\cos 0

W=40\cdot 5.9

W=236 J

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Yurem is pulling a wagon across the playground with a force of 10 N. He asks Elianna to help. She agrees and pushes the back of
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You will now examine the relationship between the number of field lines through a surface and the tangle betwcen A and E) angle
nikitadnepr [17]

Answer:

a. cosθ b. E.A

Explanation:

a.The electric flux, Φ passing through a given area is directly proportional to the number of electric field , E, the area it passes through A and the cosine of the angle between E and A. So, if we have a surface, S of surface area A and an area vector dA normal to the surface S and electric field lines of field strength E passing through it, the component of the electric field in the direction of the area vector produces the electric flux through the area. If θ the angle between the electric field E and the area vector dA is zero ,that is θ = 0, the flux through the area is maximum. If  θ = 90 (perpendicular) the flux is zero. If θ = 180 the flux is negative. Also, as A or E increase or decrease, the electric flux increases or decreases respectively. From our trigonometric functions, we know that 0 ≤ cos θ ≤ 1 for  90 ≤ θ ≤ 0 and -1 ≤ cos θ ≤ 0 for 180 ≤ θ ≤ 90. Since these satisfy the limiting conditions for the values of our electric flux, then cos θ is the required trigonometric function. In the attachment, there is a graph which shows the relationship between electric flux and the angle between the electric field lines and the area. It is a cosine function  

b. From above, we have established that our electric flux, Ф = EAcosθ. Since this is the expression for the dot product of two vectors E and A where E is the number of electric field lines passing through the surface and A is the area of the surface and θ the angle between them, we write the electric flux as Ф = E.A  

4 0
3 years ago
In a chemical reaction, molecules of hydrogen gas (H2) react with molecules of oxygen gas (O2) in a sealed reaction chamber to p
11Alexandr11 [23.1K]

Answer:

Option (B) is correct.

Explanation:

Given that the molecules of hydrogen gas (H_2) react with molecules of oxygen gas (O_2) in a sealed reaction chamber to produce water (H_2O).

The governing equation for the reaction is

2H_2 +O_2 \rightarrow 2H_2O

From the given, the only fact that can be observed that 2 moles of H_2 and 1 mole of O_2 reacts to produce 2 moles of H_2O.

As the mass of 1 mole of H_2 = 2 grams ... (i)

The mass of 1 mole of O_2 = 32 grams ...(ii)

The mass of 1 mole of H_2O = 18 grams (iii)

Now, the mass of the reactant = Mass of 2 moles of H_2 + mass 1 mole of  O_2

= 2 \times 2 + 32  [ using equations (i) and (ii)]

=4+32 = 36 grams.

Mass of the product = Mass of 2 moles of H_2O

=2\times 18 [ using equations (iii)]

=36 grams

As the mass of reactants = mass of the product.

So, mass is conserved.

Hence, option (B) is correct.

8 0
3 years ago
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