Answer:
B
Explanation:
The correct option for the question is B that is salt water. In salt water, the density of water is higher so the pressure at the end of tube containing salt water will be greater. As according to the hydrostatic law the pressure at a given point will be directly proportional to the distance travelled as well.
Momentum is conserved, so the sum of the separate momenta of the car and wagon is equal to the momentum of the combined system:
(1250 kg) ((36.2 <em>i</em> + 12.7 <em>j </em>) m/s) + (448 kg) ((13.8 <em>i</em> + 10.2 <em>j</em> ) m/s) = ((1250 + 448) kg) <em>v</em>
where <em>v</em> is the velocity of the system. Solve for <em>v</em> :
<em>v</em> = ((1250 kg) ((36.2 <em>i</em> + 12.7 <em>j </em>) m/s) + (448 kg) ((13.8 <em>i</em> + 10.2 <em>j</em> ) m/s)) / (1698 kg)
<em>v</em> ≈ (30.3 <em>i</em> + 12.0 <em>j</em> ) m/s
They are called magnets poles.
At rest because if the distance is not changing, then it is not moving any further, so it must not be moving! The time keeps going no matter what, so the distance, whether it is 0 m or 10,000 km, if the y is horizontal the distance does not change.
Answer:
A) a = 7.89 m/s²
B) a = 3.51 m/s²
C) 4.38 m/s²
D) Frictional force
E) F_f = 5552.83 N
Explanation:
A) Formula for Force is;
F = ma
Where;
m is mass
a is acceleration
We are given;
F = 10,000 N
m = 1267 kg
Thus;
10000 = 1267a
a = 10000/1267
a = 7.89 m/s²
B) We are told the car covers 394.6 m in 15 seconds.
Using Newton's third equation equation of motion, we can find the actual acceleration.
s = ut + ½at²
u is zero since the object began from rest.
Thus;
S = ½at²
394.6 = ½ × a × 15²
a = 394.6 × 2/225
a = 3.51 m/s²
C) difference in accelerations = 7.89 - 3.51 = 4.38 m/s²
D) The force that caused the difference in acceleration is frictional force
E) To find the magnitude of the force that caused the difference in acceleration, we will use the formula;
F - F_f = ma
F_f = F - ma
Where F_f is the frictional force
Thus;
F_f = 10000 - 1267(3.51)
F_f = 5552.83 N
