Yes it does work with the other body system
Answer:
23.99N
Explanation:
Given:
Pressure created by the heart = 120mm of hg
converting the pressure into the standard unit of N/m²
1mm of hg = ![\frac{1}{760}atm=\frac{1}{760}\times 1.013\times10^5N/m^2](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B760%7Datm%3D%5Cfrac%7B1%7D%7B760%7D%5Ctimes%201.013%5Ctimes10%5E5N%2Fm%5E2)
now, 120 mm of hg in N/m² will be
120mm of hg = ![\frac{12}{760}\times 1.013\times10^5N/m^2](https://tex.z-dn.net/?f=%5Cfrac%7B12%7D%7B760%7D%5Ctimes%201.013%5Ctimes10%5E5N%2Fm%5E2)
also
given effective area = 15.0 cm² = 15 × 10⁻⁴m²
Now,
Force = Pressure × Area
thus,
Force exerted will be =
× 15 × 10⁻⁴m²
or
Force exerted will be = 23.99N
Answer:
the average force exerted by seatbelts on the passenger is 5625 N.
Explanation:
Given;
initial velocity of the car, u = 50 m/s
distance traveled by the car, s = 20 m
final velocity of the after coming to rest, v = 0
mass of the passenger, m = 90 kg
Determine the acceleration of the car as it hit the pile of dirt;
v² = u² + 2as
0 = 50² + (2 x 20)a
0 = 2500 + 40a
40a = -2500
a = -2500/40
a = -62.5 m/s²
The deceleration of the car is 62.5 m/s²
The force exerted on the passenger by the backward action of the car is calculated as follows;
F = ma
F = 90 x 62.5
F = 5625 N
Therefore, the average force exerted by seatbelts on the passenger is 5625 N.
As charges move in a closed loop, they gain as much energy as they lose.
<h3>What is principle of
conservation of energy?</h3>
- According to the principle of conservation of energy, in a closed or isolated system, the total energy of the system is always conserved.
- The energy gained by the particles or charges in a closed system is equal to the energy lost by the charges.
Thus, we can conclude the following based on principles of conservation of energy;
- As charges move in a closed loop, they gain as much energy as they lose.
Learn more about conservation of energy here: brainly.com/question/166559
It depends on how many hours!
1 hour = 40km
2 hours = 80km