Answer : The entropy change for the surroundings of the reaction is, -198.3 J/K
Explanation :
We have to calculate the entropy change of reaction .
where,
= entropy of reaction = ?
n = number of moles
= standard entropy of
= standard entropy of
= standard entropy of
Now put all the given values in this expression, we get:
Therefore, the entropy change for the surroundings of the reaction is, -198.3 J/K
Answer:
ruthenium (Ru), rhodium (Rh), palladium (Pd), osmium (Os), iridium (Ir), platinum (Pt), gold (Au), silver (Ag).
Explanation:
Answer:
d hope this helps u hhwjs GD jehehj
Best Answer:<span> </span><span>LiCl
Cl and Li
glucose
BeF2
last question answer 3 strong electrostatic requires a lot of energy
does this help though??</span>