0.125 g=(0.125 g)(1000 mg/1g)=125 mg.
Then, we need 125 mg of ampicillin.
5 ml of liquid suspension contains 250 mg of ampicilling , therefore:
5 ml----------------250 mg of ampicilling
x--------------------125 mg of ampicilling
x=(5 ml * 125 mg of ampicilling) / 250 mg of ampicilling=2.5 ml
Answer: we require 2.5 ml
Basicity of an acid is the number of hydrogen ions which can be produced by one molecule of an acid
It is possible to rate your active reading skills either by using a number is a specific rate or by using a word that qualifies your performance.
<h3>What are active reading skills?</h3>
Active reading skills are a set of skills that help you read actively; this means skills to effectively read a text and understand it.
<h3>How to rate your reading skills?</h3>
In this case, you are asked to rate your ability to pay attention to your understanding, thoughts, and questions while reading. To do this you can:
Rate using numbers:
- Select a specific scale rating such as 1 to 5 or 1 10.
- Analyze honestly if you used this ability while reading the text.
- Give yourself a number. For example, if you apply this skill only sometimes while reading you can rate yourself 5 out of 10.
Rate using words:
- Select the types of words that you will use, the most common ones are frequency words such as always, sometimes, and never.
- Analyze honestly your performance.
- Find the word that best fits it.
Learn more about rate in: brainly.com/question/2278897
The number of protons found in the nucleus equals the number of electrons that surround it, giving the atom a neutral charge (neutrons have zero charge). Most of an atom's mass is in its nucleus; the mass of an electron is only 1/1836 the mass of the lightest nucleus, that of hydrogen.Hoped this helped
Answer:
0.11%
Explanation:
Without mincing words, let us dive straight into the solution to the question/problem. The first step to solve this question is to write out the chemical reaction, that is the reaction showing the dissociation of acetic acid.
CH3COOH <=======================================> CH3COO⁻ + H⁺
Initially, the amount present in the acetic acid which is = 12M, the concentration for CH3COO⁻ and H⁺ is 0 respectively.
At equilibrium, the amount present in the acetic acid which is = 12 - x, the concentration for CH3COO⁻ = x and H⁺ = x respectively. Note that the ka for acetic acid = 1.8 × 10⁻⁵.
1.8 × 10⁻⁵ = x²/ 14 - x. Therefore, x = 0.0158 M.
The next thing to do is to calculate for the percentage of dissociation, this can be done as given below:
percentage of dissociation = x/14 × 100. Recall that the value that we got for x = 0.0158 M. Hence, the percentage of dissociation = 0.0158 M/ 14m × 100 = 0.11%
