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3 years ago

1/x - 1/(x+1) ≤ 0 Please help quickly

1 answer:

7 0

$\frac{1}{x}- \frac{1}{x+1}= \frac{(x+1)-x}{x(x+1)}= \frac{1}{x(x+1)} \leq 0$

Therefore x(x+1)≤0, and if two numbers multiply to a negative number, one of them has to be negative and the other has to be positive. In this case, because x+1>x, x≤0, and x+1≥0

Therefore -1≤x≤0, and x can take up the value of any real number in the interval [-1,0]

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Solve for g.

Y_Kistochka [10]

Answer:

g =6/5 g=-5/2

Step-by-step explanation:

(5g − 6)(2g + 5) = 0

Using the zero product property

(5g − 6) =0 (2g + 5) = 0

5g-6+6 =0+6 2g+5-5=0-5

5g =6 2g =-5

5g/5 = 6/5 2g/2 =-5/2

g =6/5 g=-5/2

7 0

3 years ago

HELP ME WITH THIS MATH

tester [92]

Answer: Do you know what the total degree is but if not an algebraic equation us 148-x = 26

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

PLEASE HELP<br>Is the function linear or nonlinear y=1/x ?<br><br> A. linear B. nonlinear

Rina8888 [55]

It's nonlinear.
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8 0

3 years ago

Read 2 more answers

A model rocket is launched with an initial velocity of 200 ft per second. The height h, in feet, of the rocket t seconds after t

Solnce55 [7]

Answer:

2.10 s, 10.40 s.

Step-by-step explanation:

We know that the height of the rocket is given by the function:

$h=-16t^2+200t$

We are asked to find the time for which the height of the rocket will be 350 ft. So, for that moment, we know the height but we don't know the time; however, we know that the equation can help us to find the time, doing h=350:

$350=-16t^2+200t$

The last is a quadratic equation, which can be put in the form $at^2+bt+c=0$ and solved applying the formula:

$t=\frac{-b+-\sqrt{b^2-4ac} }{2a}$

So, let's put the equation on the form $at^2+bt+c=0$ adding $16t^2$ and subtracting $200t$ to each side of the equation; the result is:

$16t^2-200t+350=0$

So, we note that a=16, b=-200, and c=350.

Then,

$t_1=\frac{200-\sqrt{200^2-4*16*350} }{2*16}=2.10$

$t_2=\frac{200+\sqrt{200^2-4*16*350} }{2*16}=10.40$

According to the equation, that are the times for which the height will be 350 ft; that is because the rocket is going to ascend and then to fail again to the ground.

4 0

3 years ago

(6,5), 7x-3y=5 find the equation of the line that contains the given point and is parallel to the line. write the equation in sl

SVEN [57.7K]

Answer:

y = (7/3)x - 9

Step-by-step explanation:

1. Convert given equation to y=mx+b form --> y = (7/3)x - 5/3

2. Equation of new line --> y = (7/3)x + b

Note: 7/3 is the slope and for lines to be parallel they need the same slope so both equations have 7/3.

3. Plug in given values --> 5 = (7/3)(6) + b

4. Solve for b --> b = 5 - 14 b = -9

5. New line --> y = (7/3)x - 9

7 0

2 years ago