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jek_recluse [69]
3 years ago
11

Why does the vertical component of velocity for a projectile change with time, whereas the horizontal component of velocity does

not change?
Physics
1 answer:
dlinn [17]3 years ago
5 0

Answer

When a body moves in projectile motion it has two components. One of the components is a horizontal component of the velocity and another is a vertical component.

The velocity along the horizontal component does not change because there is no acceleration long horizontal component.  

Whereas velocity along vertical direction keeps on changing because the acceleration due to gravity is acting on the object. At a maximum height of the projectile velocity is equal to zero.

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Suppose you were digging a well into saturated sediments. Why is the sediment’s permeability an important factor in deciding whe
zloy xaker [14]

Answer:

The importance of the sediments permeability is that if it is permeable, water will flow easily through the sediment and thereby produce a very good supply of water for the well.

Explanation:

When digging a well into saturated sediments, the possibility of the sediment with either little saturation or full saturation being able to provide steady water supply will be limited by how permeable it is. Now, the importance of the sediments permeability is that if it is permeable, water will flow easily through the sediment and thereby produce a very good supply of water for the well.

4 0
3 years ago
A 100-kg spacecraft is in a circular orbit about Earth at a height h = 2RE .
maria [59]

To solve this problem it is necessary to apply the concepts related to the conservation of the Gravitational Force and the centripetal force by equilibrium,

F_g = F_c

\frac{GmM}{r^2} = \frac{mv^2}{r}

Where,

m = Mass of spacecraft

M = Mass of Earth

r = Radius (Orbit)

G = Gravitational Universal Music

v = Velocity

Re-arrange to find the velocity

\frac{GM}{r^2} = \frac{v^2}{r}

\frac{GM}{r} = v^2

v = \sqrt{\frac{GM}{r}}

PART A ) The radius of the spacecraft's orbit is 2 times the radius of the earth, that is, considering the center of the earth, the spacecraft is 3 times at that distance. Replacing then,

v = \sqrt{\frac{(6.67*10^{-11})(5.97*10^{24})}{3*(6.371*10^6)}}

v = 4564.42m/s

From the speed it is possible to use find the formula, so

T = \frac{2\pi r}{v}

T = \frac{2\pi (6.371*10^6)}{4564.42}

T = 8770.05s\approx 146min\approx 2.4hour

Therefore the orbital period of the spacecraft is 2 hours and 24 minutes.

PART B) To find the kinetic energy we simply apply the definition of kinetic energy on the ship, which is

KE = \frac{1}{2} mv^2

KE = \frac{1}{2} (100)(4564.42)^2

KE = 1.0416*10^9J

Therefore the kinetic energy of the Spacecraft is 1.04 Gigajules.

8 0
3 years ago
Is The neck is an example of a simple machine in the human body?
tatyana61 [14]
No it's the quite opposite simple
3 0
3 years ago
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Why dont animal cells need chloroplasts?
Zigmanuir [339]
Animals don't make Their own food. they instead depend on the food made by plants. hence no need for chloroplasts
3 0
3 years ago
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A hiker starts at point P and walks 2.0 km due east and then walks at an angle of 30 degrees north of east for 1.4 km.
olchik [2.2K]

Answer:

The magnitude of the hiker’s displacement is 2.96 km

Explanation:

Let the initial displacement of the hiker, = x = 2km

the final displacement of the hiker, = y = 1.4 km

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R' = x' + y'

Check the image uploaded for solution;

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