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kvv77 [185]
4 years ago
10

Explain why nuclear fission and nuclear fusion release large amounts of energy

Physics
2 answers:
vovikov84 [41]4 years ago
5 0

Answer:

Because the factor c^2 is huge

Explanation:

- The process of nuclear fission occurs when a heavy, unstable nucleus break apart into two or more lighter, more stable nuclei

- The process of nuclear fusion occurs when two (or more) light nuclei fuse together into a heavier nucleus

In both processes, the total mass of the final products of the process is smaller than the total mass of the initial nuclei in the process.

Therefore, this means that part of the initial mass of the nuclei has converted into energy, according to Einsten's equivalence:

E=\Delta mc^2

where

E is the energy released in the process

\Delta m is the  mass defect, which is the difference between the final total mass and the initial total mass

c=3.0 \cdot 10^8 m/s is the speed of light

Since the factor c^2 is a huge number, we can see that even if the mass defect \Delta m is tiny, these processes result in a huge amount of energy released.

Mashutka [201]4 years ago
3 0

Answer:

Sample Response: In nuclear fission, the mass of the original nucleus is greater than the mass of the products. The extra mass is converted to energy. In nuclear fusion, the total binding energy of the lighter nuclei is greater than the binding energy of the heavier nucleus. Extra energy is released during the reaction.

Explanation:

on edge

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a ball is projected with a certain angle with initial velocity u. it covers horizontal range R. With what initial velocity it mu
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1.5 u

Explanation:

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A uniform solid sphere has mass m= 7 kg and radius r= 0. 4 m. What is its moment of inertia about an axis tangent to its surface
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The moment of inertia of a uniform solid sphere is equal to 0.448 kgm^2.

<u>Given the following data:</u>

Mass of sphere = 7 kg.

Radius of sphere = 0.4 meter.

<h3>How to calculate moment of inertia.</h3>

Mathematically, the moment of inertia of a solid sphere is given by this formula:

I=\frac{2}{5} mr^2

<u>Where:</u>

  • I is the moment of inertia.
  • m is the mass.
  • r is the radius.

Substituting the given parameters into the formula, we have;

I=\frac{2}{5} \times 7 \times 0.4^2\\\\I=2.8 \times 0.16

I = 0.448 kgm^2.

Read more on inertia here: brainly.com/question/3406242

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