Question

a ball is projected with a certain angle with initial velocity u. it covers horizontal range R. With what initial velocity it must be projected keeping the angle of projection same so its horizontal range becomes 2.25R

Answer 1

Answer:

1.5 u

Explanation:

The range equation is:

R = u² sin(2θ) / g

When u = v, R = 2.25 R.

2.25 R = v² sin(2θ) / g

2.25 u² sin(2θ) / g = v² sin(2θ) / g

2.25 u² = v²

1.5 u = v