Question

A 1700kg rhino charges at a speed of 50.0km/h. what is the magnitude of the average force needed to bring the rhino to a stop in 0.50s? express your answer to two significant figures.

Answer 1

First, let's convert the initial speed of the rhino:
$v_i = 50 km/h = 13.9 m/s$
The acceleration of the rhino is given by:
$a= \frac{v_f-v_i}{t}= \frac{0-13.9 m/s}{0.5 s}=-27.8m/s^2$
where the negative sign means it is a deceleration. We can neglect the negative sign since we are interested only in the magnitude of the force applied, which is given by Netwon's second law:
$F=ma = (1700 kg)(27.8 m/s^2)=4.7 \cdot 10^4 N$

Answer 2

The magnitude of the average force needed to bring the rhino to a stop in 0.50s is about 4.7 × 10⁴ Newton

$\texttt{ }$

Further explanation

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

$\large {\boxed {F = ma }$

F = Force ( Newton )

m = Object's Mass ( kg )

a = Acceleration ( m )

Let us now tackle the problem !

$\texttt{ }$

Given:

mass of rhino = m = 1700 kg

initial speed of rhino = u = 50.0 km/h = 13⁸/₉ m/s

final speed of rhino = v = 0 m/s

time taken = t = 0.50 s

Asked:

average force = F = ?

Solution:

$F = ma$

$F = m \times \frac{v - u}{t}$

$F = 1700 \times \frac{0 - 13\frac{8}{9}}{0.50}$

$F = 1700 \times \frac{-250}{9}$

$F \approx -4.7 \times 10^4 \texttt{ Newton}$

$\texttt{ }$

Learn more

• Impacts of Gravity : brainly.com/question/5330244
• Effect of Earth’s Gravity on Objects : brainly.com/question/8844454
• The Acceleration Due To Gravity : brainly.com/question/4189441
• Newton's Law of Motion: brainly.com/question/10431582
• Example of Newton's Law: brainly.com/question/498822

$\texttt{ }$

Answer details

Grade: High School

Subject: Physics

Chapter: Dynamics

$\texttt{ }$

Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant